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H2(g) + S(s) —> H2S + 20.6 kJ

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4d ago

The reaction that shows the enthalpy of formation of H2S as -20.6 kJ/mol is: 2H2(g) + S(s) → 2H2S(g) with ΔH = -20.6 kJ/mol. This means that forming 1 mole of H2S from its elements H2 and S releases 20.6 kJ of energy.

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Q: Which reaction shows that the enthalpy of formation of H2S is Hf -20.6 kJmol?
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