there are 3 sig figs. 4, 0, and 5 are the sig figs

two sig figs

There are 3 sig figs.

5 sig figs

There are four sig figs in 1.032

There are two sig figs in 290.

2.35 has 3 sig figs.

61 has 2 sig figs.

13.00 has 4 sig figs.

There are five sig figs

There are three sig figs in 4890.

There are three sig figs in 1.05.

There are four sig figs in 2.905.

There are 4 sig figs in 20.13

6.002 has four sig figs.

There are two sig figs in 3700000.

There are four sig figs in 60.55.

There are eight sig figs in 57.115102.

There are five sig figs in 4.1275.

All five of them are sig figs

It is: 124.68 rounded to 5 sig figs.

There are four sig figs in 43.74 km.

it is 10 sig figs but i don't understand the question?

Depending on how many significant figures you want, it can be2.421200x10^6 (7 sig figs)2.42120x10^6 (6 sig figs)2.4212x10^6 (5 sig figs)2.421x10^6 (4 sig figs)2.42x10^6 (3 sig figs)2.4x10^6 (2 sig figs)2x10^6 (1 sig fig)

There are 3 sig figs becasue when you multiply two numbers you take the same number of sig figs as the multiple with the fewest sig figs. 0.280 and 3.70 both have 3 sig figs.