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Why are the equipotential lines near conductor surfaces parallel to the surface?
Wiki User
∙ 11y ago
For conductors, the electric field perpendicular to its surface and no field exist within the conductor. As a result the equipotential lines are found near the surface. They are parallel to the surface since equipotential are perpendicular to field lines.
Wiki User
∙ 11y ago
Wiki User
∙ 12y agoCharged surfaces are linked by an electric field, which is represented by lines of force that are perpendicular to the charged surfaces. A voltage gradient exists along the direction of these lines of force. So, for each line of force, those points that exist at identical potentials can be linked to show lines of equipotential, and these lie at right angles to the lines of force.
Lines of equipotential visually represent the voltage gradient within the insulating medium between two charged surfaces, in much the same way that gradient lines are used on a map to shown physical gradients on land surfaces -i.e. closer together the lines of equipotential are, the steeper the voltage gradient. If the voltage gradient is steeper than the insulating medium can withstand, then the insulation will break down.
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What is an equipotential surface?
It's a surface over which electric charges are evenly distributed, caused by the mutual repulsion between charges of the same polarity.
Why TEM wave is not supported by hollow waveguide?
Arif Ullah khan utman kheel this is because for conductor E parallel is zero this means that the surface of the wave guide is at equipotential and this potential follow the laplace equation .it means that there is no maxima and minima inside the wave guide . this means that the electric field inside zero . hence the TEM do not exist in wave guide only TE and TM can be exist . if we place some conductor in the wave guide then the conductor inside will not be equipotential and the TEM waves can be exist . like in Coaxial cables
Why TEM mode does not exist in waveguide?
for TEM u need to a magnetic field (H) linked to an electric field .for this u need to a J relative to E (E=sigma J). because [curl H = J] but optical fiber is dielectric wave guide and sigma is zero and u only have dD/dt so there isn't H linked to E.
What is a grounded conductor used for and what color is it required to be by NFPA 70 the national electric code?
A grounding conductor is a means for providing safety for users of electrical devices that may have experienced an internal failure that causes an electrical short to metallic surfaces. In theory, such a short to a GROUNDED surface would quickly result in overcurrent or ground-fault interruption of the circuit, resulting in an dead but safe circuit. NEVER "reset" a GFCI while holding the attached device or without discovering what caused it to trip. Were it not for a grounding conductor, the user could become the "grounding conductor" by accident, causing electrocution. Grounding conductors maybe bare (copper) wires or have green insulation, or green with a yellow stripe (also used for bonding) or other green markings (green screws, green clips, green wire nuts, etc). Grounded appliance plugs were not required in the NEC until the 1960s.
How high above bar do you hang pendant lights?
There is no set height. Most smaller surfaces can be lit at about 28" above the surface top, while larger surfaces may warrant a height of 32 to 34 inches. The farther away the light is, the larger pool of light it casts, but the less bright it is. Anywhere from 28 to 34 inches is best for most situations. It is really your choice.
Why must electric field line be perpendicular to equipotential surfaces?
If the field lines were not perpendicular to the surface, then they could be decomposed into components perpendicular and parallel to the surface. But if there is an E-field along the surface, the surface is no longer an equipotential.
What is the shape of equipotential surface due to a point charge?
concentric spherical surfaces
Why TEM modes does not exist in wave guides?
Arif Ullah khan utman kheel this is because for conductor E parallel is zero this means that the surface of the wave guide is at equipotential and this potential follow the laplace equation .it means that there is no maxima and minima inside the wave guide . this means that the electric field inside zero . hence the TEM do not exist in wave guide only TE and TM can be exist . if we place some conductor in the wave guide then the conductor inside will not be equipotential and the TEM waves can be exist . like in Coaxial cables
What is the geometrical shape of equipotential surface due to single isolated charge?
what is the geometrical shape of equipotential surface due to single isolated charge
Are the field lines for the parallel electrodes parallel everywhere?
For parallel electrodes, the field lines are all parallel to each other, since each electrode acts as an equipotential surface, meaning it has the same potential throughout its entire surface, except at the ends, where the field lines are no longer parallel to the other field lines. Hope this helps!
How many surfaces does a trapezoid have?
A trapezoid has one surface and its surface area in square units is 0.5*(sum of parallel sides)*height
Are the voltages across all branches of a parallel circuit the same?
In a parallel circuit, all the branches are joined together at their start and again at their end by a conductor (usually wire).Now, the surface of a conductor (ideally) is an equipotential surface. That is, any point of its surface has the same electric potential.And since the voltage across each branch equals the difference in electric potentials between its start and its end, and these potentials are the same for every branch, it follows that the voltages across each branch must be equal to each other.
Is any force is required to move a small charge on equipotential surface?
yes
What is rubbing of one object or surface?
Rubbing the surfaces of two objects together is friction. This requires forces parallel to the surfaces and usually accompanied by wear and a rise in temperature.
Why electric lines of force intersect equipotential surface at right angles?
As we know equipotential surface means there is no potential difference that is no work is done on surface.so lines of force must intersect surface at right angles to satisfy this statement,so that net work is zero.
What is the work done in moving a charge of 10 nC between two points on an equipotent surface?
0, because its equipotential surface
What is the amount of work done in moving a 100nc charge between two points 5 cm apart on an equipotential surface?
An equipotential surface has the same value of potential. Thus, work done would be zero. Work done = Charge X Potential difference
