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Because if you multiply a negative number three times, the product will be negative.
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Why is it possible to find a real cube root of a negative number but not a real square root of a negative number?
You cannot get real square root of a negative number because two numbers multiplied by themselves are always positive You can always get a real cube root of a negative number because three negative numbers multiplied by themselves give a negative .
Can you cube root negative two?
yes, you can find a real root to the cube root of any negative real number. There will also be two complex roots which satisfy it, as well.
Cube root of 7 is a surd but is cube root of negative seven a surd?
I am pretty sure that the cube root of negative seven is a surd. I checked on the calculator.......and it showed a negative number.....??I think when it is not a surd...it's supposed to say error, so the number probably means that it is a surd..
What is the answer to negative 2 cube root of 54?
Negative 2 (times) cube root of 54 = -7.55953 Negative 2 (plus) cube root of 54 = 1.77976
How come the function y cube root x2 - 1 has the domain -infinity infinity What is the procedure to coming to this solution?
1
Is the cube root of a negative number positive or negative?
The cube root of a negative number is negative
Can you find the cube root of a negative number If so is it positive or negative?
The cube root of a negative number is negative.
Is cube root of negative nine terminates?
No, the cube root of -9 is an irrational number.
Can the cube root of a positive number ever be a negative number?
No.
Why is it possible to find a real cube root of a negative number but not a real square root of a negative number?
You cannot get real square root of a negative number because two numbers multiplied by themselves are always positive You can always get a real cube root of a negative number because three negative numbers multiplied by themselves give a negative .
Can you cube root negative two?
yes, you can find a real root to the cube root of any negative real number. There will also be two complex roots which satisfy it, as well.
Cube root of 7 is a surd but is cube root of negative seven a surd?
I am pretty sure that the cube root of negative seven is a surd. I checked on the calculator.......and it showed a negative number.....??I think when it is not a surd...it's supposed to say error, so the number probably means that it is a surd..
How do you find the cube root of a negative number?
If the negative number is "-a", then you can say the cube root is "-(cube root of a)" Because if you cube a negative number, you get a negative number. So if you cube root a negative number, you get a negative number. Ex) cube root of -8 = -2 Because (-2)^3 = -8 But if you want to find the complex cube roots, you can make an equation: "x^3=-a" or "x^3+a=0" We know one of the roots is "-(cube root of a)" so you can factor the equation by (x+(cube root of a)) And then you use the quadratic formula for the quadratic equation you're left with. Ex) x^3=-8 or x^3+8=0 Since -2 is a root, factor it by (x+2) x^3+8=(x+2)(x^2-2x+4) Using the quadratic formula, you get "1+i√3" and "1-i√3" Therefore the three cube roots of -8 is <"-2", "1+i√3", "1-i√3">
What is the answer to negative 2 cube root of 54?
Negative 2 (times) cube root of 54 = -7.55953 Negative 2 (plus) cube root of 54 = 1.77976
What is the real number root of -25?
There is no real number [square] root of a negative number. There is a real cube root and a real fiftth root etc, but root, by itself, implies square root.
Can a negative have a cube root?
Yes as for example the cube root of -27 is -3
How come the function y cube root x2 - 1 has the domain -infinity infinity What is the procedure to coming to this solution?
1
