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You don't need moles to solve stoichiometry problems. What you do need to do is to turn things (amounts) into the same nomenclature. If you want to turn grams into liters you need to go through several steps to get from grams to liters. For example if you have 20 grams of a substance and the atomic weight (from the Periodic Table) of one molecule of the substance is 40 grams, you need to convert to milligrams. 40 grams = 40,000 mg (1gm=1000mg). So divide 40,000mg by 40 gm. 20gm = 40,000 mg / 40 mg. The grams cancel each other out and you're left with 20 x 40,000 mg / 40. Now you need to get rid of the milligrams. 1 mg = 1 ml so continue with your problem by dividing 40,000 ml by 40,000 mg. Now the mg's cancel each other out and you have 20 x 40,000 x 40,000 ml divided by 40 x 40,000. Now turn ml into liters. 1000 ml = 1 liter so add to your equation 40,000 ml = 10 liters. The ml cancel each other out and you have: 20 x 40,000 x 40,000 x 10 divided by 40 x 40,000 x 40,000. The two 40,000's on top cancel out the two 40,000's on the bottom so you have 20 x 10 divided by 40 which = 200 divided by 40 which equals 5 liters. Divide by 5 and you get 1 liter. The trick is to draw a long line and put the multipliers on top and the divisors below with up and down lines between the sections. If there is something on top that is also on the bottom, they cancel each other out. That can be numbers or units of measurements. This method allows you to convert almost anything to anything else. All you have to know are the conversion numbers (like how many killograms = 1 pound). As you can see, you can even go from metric to US numbers and from solids to liquids. Good luck!
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Why do we need to convert mass to moles in stoichiometry problems?
Converting mass to moles in stoichiometry problems is necessary because chemical reactions are based on the number of molecules involved, not their weight. By converting mass to moles, we can accurately determine the amount of each substance involved in a reaction and calculate the correct ratios for the reaction to proceed.
Why do you need to convert mass to moles in stoichiometry problems?
Converting mass to moles in stoichiometry problems is necessary to determine the amount of reactants or products involved in a chemical reaction. This conversion allows you to compare the amounts of different substances based on their molar quantities rather than their masses, making it easier to balance equations and calculate the quantities of reactants needed or products produced.
What Fewer steps are required to solve stoichiometry problems when?
Fewer steps are required to solve stoichiometry problems when the given quantities are well-balanced in terms of moles and when the molar ratios in the balanced chemical equation are easy to work with. This simplifies the calculations and reduces the need for additional conversions or adjustments.
How do you solved a volume to volume problems in stoichiometry?
To solve volume-to-volume problems in stoichiometry, you first need a balanced chemical equation. Convert the given volume of one substance to moles using the molarity provided (if applicable). Apply the stoichiometry ratios from the balanced equation to find the volume of the other substance in the reaction. Remember to convert between units as needed.
How many moles of ammonia are produced from the reaction of 90.0 L of nitrogen?
8,038 moles of ammonia were produced.
Why do we need to convert mass to moles in stoichiometry problems?
Converting mass to moles in stoichiometry problems is necessary because chemical reactions are based on the number of molecules involved, not their weight. By converting mass to moles, we can accurately determine the amount of each substance involved in a reaction and calculate the correct ratios for the reaction to proceed.
Why do you need to convert mass to moles in stoichiometry problems?
Converting mass to moles in stoichiometry problems is necessary to determine the amount of reactants or products involved in a chemical reaction. This conversion allows you to compare the amounts of different substances based on their molar quantities rather than their masses, making it easier to balance equations and calculate the quantities of reactants needed or products produced.
What Fewer steps are required to solve stoichiometry problems when?
Fewer steps are required to solve stoichiometry problems when the given quantities are well-balanced in terms of moles and when the molar ratios in the balanced chemical equation are easy to work with. This simplifies the calculations and reduces the need for additional conversions or adjustments.
How do you solved a volume to volume problems in stoichiometry?
To solve volume-to-volume problems in stoichiometry, you first need a balanced chemical equation. Convert the given volume of one substance to moles using the molarity provided (if applicable). Apply the stoichiometry ratios from the balanced equation to find the volume of the other substance in the reaction. Remember to convert between units as needed.
How many moles of ammonia are produced from the reaction of 90.0 L of nitrogen?
8,038 moles of ammonia were produced.
How many milliliters of 0.248M HCl are needed to react with 1.36 grams of zinc to produce hydrogen?
First, write a balanced equation for this reaction. The reactants are HCl and Zn and the products are ZnCl2(aq), and H2(g). For how to write a balanced equation, see the Related Questions to the left. Then, convert the grams of Zn into moles of Zn. To do that, see the Related Questions to the left. Then use stoichiometry to determine how many moles of HCl are necessary to react with that number of moles of Zn. See the Related Questions to the left for how to solve stoichiometry problems. Finally, determine how many milliliters of solution you need to get that many moles of HCl. To do that, use this equation: number of moles = number of liters * molarity
What number of molesof SrCl2'is consumed when 54g of ZnCl2 is produced?
To find the number of moles of SrCl2 consumed, you need to set up a stoichiometry ratio using the balanced chemical equation between SrCl2 and ZnCl2. First, calculate the number of moles of ZnCl2 produced from 54g. Then, use the stoichiometry ratio to determine the number of moles of SrCl2 consumed in the reaction.
How to use stoichiometry determine the concentration of a substance?
To use stoichiometry to determine the concentration of a substance, you need to first balance the chemical equation for the reaction involving the substance. Next, determine the moles of the known substance and use the balanced equation to relate it to the moles of the unknown substance. Finally, calculate the concentration of the unknown substance in terms of moles per liter based on the volume of the solution.
How do you solve stoichiometry problems?
To solve stoichiometry problems, you must first do two very important things.1) Write a balanced equation for the reaction.2) Convert all amounts of products and/or reactants in the question into moles.To find out how to do both of these see the Related Questions links to the left of this answer. (Note that if the question involves gases, and the amount of gas is given as a volume, you need to use the Ideal Gas Law. How to do that is also listed under the Related Questions).Once all quantities have been converted to moles and you have a balanced reaction, you are ready to actually use stoichiometry. The idea of stoichiometry is really quite simple. The coefficients (or numbers) in front of each reactant and product in the balanced chemical reaction tells you the ratio of how much of each you will react/produce. Let's take a simple example: the reaction of hydrogen gas (H2) with oxygen gas (O2) to form water (H2O). 2H2 + O2 ---> 2H2O In the balanced reaction, there is a 2 in front of the H2, and although nothing is written, that means that there is really 1 in front of O2, and a 2 in front of H2O. Stoichiometry tells us that because of the way the numbers in balanced reaction came out, we need two molecules of H2 to react with each one molecule of O2, and also, that this will form 2 molecules of water. I can say the same thing using moles: For each mole of O2 I react, I need 2 moles of H2, and I will produce 2 moles of O2. All I'm using is the ratio of the coefficients from the balanced reaction. That is stoichiometry! So, using this I can say things like: -- If I reaction 0.5 moles of O2 completely, I will make 1 mole of water-- If I made 4 moles of water, then I consumed 4 moles of H2 and 2 moles of O2.-- If I want to completely react 5 moles of H2, then I need 2.5 moles of O2 (and I will get 5 moles of H2O). Makes sense? The ratio of H2 to O2 to H2O is 2:1:2, and that always holds for this reaction.Now let's make it a bit more complicated.--Problem: If I burn 10 grams of methane, how many grams of CO2 will be produced?-- Answer: As I said, to solve this problem we need two things: a balanced reaction, and to convert all quantities to moles. First, let's write a balanced reaction. In this reaction, methane gas (CH4) gets burned in oxygen (O2) to form carbon dioxide (CO2) and water vapor (H2O). The balanced reaction is:CH4 + 2O2 --> CO2 + 2H2ONotice the ratio is now 1:2:1:2 (reading the reaction from left to right). So that tells me for every mole of CH4 I react, I need 2 moles of O2, and I will get out 1 mole of CO2 and 2 moles of H2O.Now, I need to convert the 10 grams of methane into moles, because stoichiometry only works for moles and NOT grams! So I use the molar mass of CH4, which is 12.011+4*1.0079 = 16.0426 grams per mole. So to convert to moles, I just divide: 10 grams ÷ 16.0426 gram/mole = 0.6233 moles From the stoichiometry, I now know that if I react 0.6233 moles of methane, I will need twice that many moles of oxygen, or 1.2467 moles O2, and I will get 0.6233 moles of CO2 and 1.2467 moles of H2O as products. But the question asked for a number of grams of CO2, not moles. So once I'm done using stoichiometry, I convert back to grams, now using the molar mass of CO2 (which is 12.011 + 2*15.999 = 44.009 g/mol). So 0.6233 moles of O2 is: 0.6233 moles * 44.009 grams/mole = 27.4308 grams of CO2 Notice that the ratio of moles of CH4 to CO2 is 1 to 1, but the ratio of the weights is totally different. Remember, STOICHIOMETRY ONLY WORKS ON MOLES! I can also find how many grams of water I'll produce, just for fun! The molar mass of water is 15.999 + 2*1.0079 = 18.0148 g/mol. So to convert 1.2467 moles H2O to grams: 1.2467 moles * 18.0148 gram/mole = 22.4591 grams of H2Oto answer stoichiometry problems there are several ways.one way is the mole concept(mol)-always remember Avogadro's number which is 6.02x10^23.eg. how many atoms are there in 1 mol of glucose(C6H12O6)?1 mol C6H13O6 x 6.02x10^23= 6.02x19^231 mol C6H12O6cancel 1 mol C6H12O6 leaving the answer.
How many moles of NaCl would form from 3.25 moles of NaHCO3?
To find the moles of NaCl formed from NaHCO3, we need to consider the stoichiometry of the reaction. The balanced equation is: 2 NaHCO3 -> Na2CO3 + H2O + CO2 Therefore, for every 2 moles of NaHCO3, we get 1 mole of NaCl. Therefore, 3.25 moles of NaHCO3 would produce 1.625 moles of NaCl.
How do you calculate mass of pure product in stoichiometry?
To calculate the mass of a pure product in stoichiometry, you need to use the stoichiometric coefficients from the balanced chemical equation to convert the given amount of reactant into the desired product. Once you have determined the moles of the product, you can then convert moles to grams using the molar mass of the product. This will give you the mass of the pure product produced.
How many moles of product?
To determine the moles of a product in a chemical reaction, you need to use the stoichiometry of the reaction. This involves converting the molar amount of one reactant to the molar amount of the product using the mole ratios from the balanced chemical equation.
