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That's not always the case. One formula for power dissipated is:
P = IR
So, a higher resistance means that more power is dissipated - if the current is the same. The reason for this is precisely that resistance is related to the conversion of electrical energy into heat.
However, if you put a higher resistance across a specific voltage, you'll get less power dissipation, not more, since less current will flow at a higher resistance.
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What is the formula for exponential decay?
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Find the area of the largest square incribed in a circle?
A circle of radius, r, has area pi r2. The largest square inside it is made up of four isosceles triangles whose equal sides are of length, r, and thus has area 1/2 r2. Thus the area of the contained square is 2 r2.
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Reactance is not dissipate energy so why you are calculating in the account of resistance?
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How can you work out the power of a resistor?
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No, because the power dissipated in a resistor is proportional to the square of the current through the resistor but only directly proportional to the resistance of the resistor (I^2 * R) and the current through the lower value resistor will be higher than the current through the higher value resistor, the lower value resistor will usually dissipate more power.
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What is the power dissipated by a resistance of 23ohm connected to a 400v peak to peak square wave source of 150hz?
Most resistors dissipate power as heat for current in any direction, so the frequency becomes irrelevant to this part of the question, but rather how long the circuit is on. The square wave tells me the power is always at 400V for all peaks, question becomes P = E * I = E2/R = watts.
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