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No. Only the length of the string and the value of g does.
yes! it definitely depends on the length of the string.when the string is long it takes more time unlike when the string is short it takes lesser time........
The shorter the string - the faster the oscillation.
Well compare a pendulum with swing. If the swing length is short, you will quickly return back to your middle position. Similarly in a pendulum if you have a long string, the time take to complete one swing will be more. This means Time period is directly proportional to the increase in length . But by various experiments, they have found that T Is proportional to sq root of length. T = 2pi sq root of (length /g) If you wish to clarify physics doubts, please subscribe to my handle @Raj-bi7xp
-- friction in the pivot -- air moving past the pendulum -- the effective length of the pendulum -- the local acceleration of gravity
No. Only the length of the string and the value of g does.
yes! it definitely depends on the length of the string.when the string is long it takes more time unlike when the string is short it takes lesser time........
The shorter the string - the faster the oscillation.
The mass of the pendulum, the length of string, and the initial displacement from the rest position.
multiply the length of the pendulum by 4, the period doubles. the period is proportional to the square of the pendulum length.
The period of the pendulum is (somewhat) inversely proportional to the square root of the length. Therefore, the frequency, the inverse of the period, is (somewhat) proportional to the square root of the length.
A longer pendulum will have a smaller frequency than a shorter pendulum.
yes it does because the shorter the string is the faster it will go (:
Well compare a pendulum with swing. If the swing length is short, you will quickly return back to your middle position. Similarly in a pendulum if you have a long string, the time take to complete one swing will be more. This means Time period is directly proportional to the increase in length . But by various experiments, they have found that T Is proportional to sq root of length. T = 2pi sq root of (length /g) If you wish to clarify physics doubts, please subscribe to my handle @Raj-bi7xp
For a simple pendulum, consisting of a heavy mass suspended by a string with virtually no mass, and a small angle of oscillation, only the length of the pendulum and the force of gravity affect its period. t = 2*pi*sqrt(l/g) where t = time, l = length and g = acceleration due to gravity.
A pendulum is a piece of string attached to a 20 g mass that if you double the length it will take twice as long to swing.
The period increases as the square root of the length.