T=2pi sqrt(m/k) here,
m=mass of the body which is oscillating
k=force or spring constant
k=m.w2 after substituting value of k in the first equation we get,
T=2pi/w
and hence we can see in any case it does not depend on the mass of the body as it cancels down when we put the value of k in the equation.
The time of a period doesn't depend on the mass of the Bob(that'll be a mass spring system) It also doesn't depend on Friction..
Unless it's in a ship that is accelerating, a simole pendulum will not swing in free space. If it's in a ship that's accelerating, its period will depend on the magnitude of the acceleration.
The period of a pendulum is totally un-affected by the mass of the bob.The time period of pendulum is given by the eqn.T=2*PIE*(l/g)1/2 ;l is the length of pendulum;g is the acceleration due to gravity.'l' is the length from the centre of suspension to the centre of gravity the bob.ie.the length of the pendulum depends on the centre of gravity of the bob,and hence the distribution of mass of the bob.
It does depend on the force of gravity where the pendulum is located. There are other factors that it depends on but their contribution, in normal circumstances, is negligible enough to ignore.
For a simple pendulum, consisting of a heavy mass suspended by a string with virtually no mass, and a small angle of oscillation, only the length of the pendulum and the force of gravity affect its period. t = 2*pi*sqrt(l/g) where t = time, l = length and g = acceleration due to gravity.
The time of a period doesn't depend on the mass of the Bob(that'll be a mass spring system) It also doesn't depend on Friction..
The PERIOD of a Simple Pendulum is affected by its LENGTH, and NOT by its Mass or the amplitude of its swing. So, in your case, the Period of the Pendulum's swing would remain UNCHANGED!
The length of the pendulum, and the acceleration due to gravity. Despite what many people believe, the mass has nothing to do with the period of a pendulum.
If you make the simplifying assumption that everything except the bob is massless, then the mass of the bob has no effect on the period.
Mass oscillation time period = 2 pi sq rt. (m/k) Pendulum oscillation time period = 2 pi sq rt. (l/g)
The period of a simple pendulum is independent of the mass of the bob. Keep in mind that the size of the bob does affect the length of the pendulum.
When the length of a pendulum is increased, by any amount, its Time Period increases. i.e. it moves more slowly. Conversely, if the length is decreased, by any amount, its Time Period decreases. i.e. it moves faster.
Unless it's in a ship that is accelerating, a simole pendulum will not swing in free space. If it's in a ship that's accelerating, its period will depend on the magnitude of the acceleration.
The period of a pendulum is totally un-affected by the mass of the bob.The time period of pendulum is given by the eqn.T=2*PIE*(l/g)1/2 ;l is the length of pendulum;g is the acceleration due to gravity.'l' is the length from the centre of suspension to the centre of gravity the bob.ie.the length of the pendulum depends on the centre of gravity of the bob,and hence the distribution of mass of the bob.
Period is independent from mass. Because period, or T = 1/f and f = cycles/time, then T = time/cycles.
This pendulum, which is 2.24m in length, would have a period of 7.36 seconds on the moon.
It does depend on the force of gravity where the pendulum is located. There are other factors that it depends on but their contribution, in normal circumstances, is negligible enough to ignore.