I assume you mean when the bucket is spinning, so I will answer as such:
If a bucket spins at a sufficient speed, with a sufficient radius, then it will generate a centrifugal force (in reality there is no such thing, but mathematically we can use it to describe the force acting on the bucket and its contents) strong enough to overcome gravity.
Centrifugal force is described as follows:
Fc = mv^2/r
where Fc is the force pushing the water inside of the bucket, m is the mass of the water (that's the only thing we care about right now--I'll explain why later), v is the velocity, and r is the radius you're swinging the bucket about.
Now, the water won't fall out if and only if...
Fc ≥ Fg
where Fg = the force of gravity trying to pull it out of the bucket.
So really, we'd have...
mv^2/r ≥ (9.8)(m)
And here's why the mass doesn't matter: it cancels out! Simplify the equation on both ends to reach:
v^2/r ≥ 9.8
now, 9.8 is an ACCELERATION: it's 9.8m/s^2
To find out whether or not the water falls out of the bucket, fill in the velocity (tangential, not angular: that is, if you "let the bucket go" at any point, v= the speed it would fly away from you) and the radius you're spinning it about. If, when you perform this operation, you result in a number larger than 9.8 meters per second squared, the water stays in the bucket!
Because the centripetal reaction force of the rotating bucket exceeds the force of gravity attempting to pull the water out.
Yeah dhh!!
because there is no force applied on the bucket
it happens because the air pressure counteracts the gravitational pull of the water which allows the water to stay in the bucket centrifugal acceleration and gravitational acceleration are indistinguishable from each other despite the fact that they arise from different causes. Therefore if v2/r > Gm/r2 then the water will obey the centrifugal acceleration over the gravitational. sorry, but the guy talking about air pressure is incorrect. the force pushing the water up from centripital force is greater than that of gravity, therefore it will not fall out.
it will
Because the centripetal reaction force of the rotating bucket exceeds the force of gravity attempting to pull the water out.
a bucket...
poo in it how do you ground a bucket of water
Pour a bucket of water.
get a bucket, go to a fountain or an other water spot, click on use bucket and click on the water.
it would fall down because of the gravitational pull
No, I haven't. But, when the bucket is in the water, the weight is supported by the water in the well. Once the bucket is raised out of the water, the weight is no longer supported, and the full weight of the bucket and the water within the bucket is felt as it is raised towards the surface.
You would cool a bucket by putting ice into the water.
It depends on the bucket size, but usually a standard size bucket would hold a few litters of water.
The salt solution in the bucket is 10% of the salt solution in the bag. The bagged solution has a higher density than the bucket solution; therefore, the bagged solution will most likely fall to the bottom of the bucket as the bucket water is displaced above it -- assuming there is no air in the bag, the density of the bag material is negligible, and the salt is fully dissolved in the water. Details: = The solution in the bucket is 0.3% while the solution is the bag is 3%. Thus, the solution in the bucket has less concentration of salt than the solution in the bag. Hence, the solution in the bucket is hypotonic to the solution in the bag.
Well, if I am correct the water in the bucket stays in there because of inertia and centripetal force. The water wants to come out of the bucket but inertia prevents the water to come out of the bucket. That is all I know I don't know how centripetal force helps the water stay in the bucket though. Hoped this helped you a bit.
There was a bucket at the well that she picked up and used