The gain of a transister stage is determined by its biasing circuit design. The emitter of a transistor is affected by the input signal on the base. If the base forward biases the transistor, the emitter feels the potential of the colector. If the base reverse biases the transistor, the emitter is isolated from the collector and feels the potential of the emmiter biasing circuit.
The output signal at the emmiter is representitive of the signal on the base, 180 degrees out of phase. The amplitude of the output signal will be larger, depending on the biasing circuit design.
54.6dB
A: By applying two known DC input with a known gain the output will be there to prove the difference.
1)in cc configuration we use to get the low output impedence where as in ce we use to get the high output impedence. 2)in cc amplifier we use to have the voltage gain equal to unity where as in ce amplifier we use to have the high voltage gain. 3)in cc amplifier there is high power gai which is used for impedence matching where as in ce amplifier due to the high voltage gain the impedence matching is less impossible.
gain in an op-amp is the output voltage divided by input voltage. for the inverting amplifier , gain(Av)=-(Rf/Ri) ,where Rf => resistance of the feedback path & Ri=> inverting input terminal resistance for the non-inverting amplifier , gain(Av)=(1+(Rf/Ri)) , where Rf => same & Ri=> non inverting input terminal resisance
A voltage amplifier (high input and output impedances) with a gain of 83.5 dB will amplify a signal of 1 millivolt to an output of 15 volts.
Since we know that the amplifier gain is given by A=Output voltage/input voltage (where A is the amplifier gain) So, it can be written as output voltage=A*input voltage, so when the output part increases gain increases but when input part increases gain decreases
Voltage gain is the ratio of the output voltage of an amplifier to its input voltage.
The power gain of an amplifier having an input of 20W and an output of 20mW is 0.001. Expressed in decibels, that is a gain of -30db. (log2 0.001 * 3)If you meant an output power of 20MW (mega instead of milli), the gain is 1,000,000, or +60db.
The power gain of an amplifier having an input of 20W and an output of 20mW is 0.001. Expressed in decibels, that is a gain of -30db. (log2 0.001 * 3)If you meant an output power of 20MW (mega instead of milli), the gain is 1,000,000, or +60db.
Answer is GAIN
54.6dB
It never referred as ratio but Rather a gain A in the form of output divided by the input and implies voltage A=gain. basically is input resistance divided by the feedback resistance
Gain, usually measured in decibels, is the ratio of output to input power. A more sensitive amplifier will have higher gain settings requiring less input signal.
A: By applying two known DC input with a known gain the output will be there to prove the difference.
There are a number of characteristics found in a common emitter amplifier. Not only are the parameters considered, but also their performance. Characteristics and performance are: voltage gain/ medium; current gain/ medium; power gain/ high; input / output phase relationship/ 180 degrees; input resistance/ medium; and output resistance/ medium.
1)in cc configuration we use to get the low output impedence where as in ce we use to get the high output impedence. 2)in cc amplifier we use to have the voltage gain equal to unity where as in ce amplifier we use to have the high voltage gain. 3)in cc amplifier there is high power gai which is used for impedence matching where as in ce amplifier due to the high voltage gain the impedence matching is less impossible.
In a two stage amplifier the gain (ratio of the output to the input quantity) of the first stage is amplified again in the second stage so the gain of a two stage amp is the product of the gain of two individual stages which is sufficient enough to drive the output device as compared to a single stage amplifier.