Boron has two few valence electrons to ever obtain a full octet.
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∙ 15y agoBoron is an exception to the octet rule because it only has six electrons in its outer shell, so it can form stable compounds with fewer than eight electrons. This occurs because boron is in the second row of the Periodic Table and can form stable compounds by sharing fewer electrons.
No, BeF2 does not obey the octet rule. Beryllium forms bonds using only two valence electrons instead of the eight needed to satisfy the octet rule. This is because beryllium is in the second period of the periodic table and can have an expanded valence shell.
First, it helps to draw out the Lewis structure. Boron, being the least electronegative element is in the center, with the three Bromines singly bonded around it. Each Br has an octet of electrons (3 lone pairs plus the single bond) and there are no electrons left over to go onto the Boron. This leaves Boron without an octet, but Boron is an exception to the octet rule so that's okay. So, no BBr3 does not follow the octet rule.
No, BCl3 does not follow the octet rule as boron only has 6 valence electrons in this molecule. Boron can form stable compounds with less than an octet due to its electron deficiency.
NH3 is not an exception to the octet rule. Nitrogen (N) in NH3 has a total of 8 valence electrons (5 from nitrogen and 3 from hydrogen), fulfilling the octet rule. Nitrogen has 3 bonded pairs and 1 lone pair of electrons, following the octet rule.
HCl doesn't follow the octet rule because hydrogen can only have 2 valence electrons and doesn't need a full octet to achieve a stable configuration.
No, BeF2 does not obey the octet rule. Beryllium forms bonds using only two valence electrons instead of the eight needed to satisfy the octet rule. This is because beryllium is in the second period of the periodic table and can have an expanded valence shell.
First, it helps to draw out the Lewis structure. Boron, being the least electronegative element is in the center, with the three Bromines singly bonded around it. Each Br has an octet of electrons (3 lone pairs plus the single bond) and there are no electrons left over to go onto the Boron. This leaves Boron without an octet, but Boron is an exception to the octet rule so that's okay. So, no BBr3 does not follow the octet rule.
No, BCl3 does not follow the octet rule as boron only has 6 valence electrons in this molecule. Boron can form stable compounds with less than an octet due to its electron deficiency.
It is limit, stus
Yes, oxygen is an exception to the octet rule. Molecular oxygen can have two unpaired electrons making it a biradical molecule.
NH3 is not an exception to the octet rule. Nitrogen (N) in NH3 has a total of 8 valence electrons (5 from nitrogen and 3 from hydrogen), fulfilling the octet rule. Nitrogen has 3 bonded pairs and 1 lone pair of electrons, following the octet rule.
It is one of many, many exceptions to the octet rule. Hydrogen does NOT require 8 electrons.
In general, boron will form 3 covalent bonds, using each of its 3 valence shell electrons (sharing them). This will of course violate the octet rule, but obeys the sextet rule, and this is what makes boron stable. It (along with aluminum, eg.) do not obey the octet rule.
HCl doesn't follow the octet rule because hydrogen can only have 2 valence electrons and doesn't need a full octet to achieve a stable configuration.
PF5 obeys the octet rule as it has 5 bonding pairs of electrons around the central phosphorus atom, satisfying the octet. Cs2 does not follow the octet rule as Cs is in Group 1 and can only form ionic bonds. BBr3 is an exception to the octet rule as boron has only 6 electrons around it due to the empty d orbital. CO3 2- also obeys the octet rule as each oxygen atom has a complete octet.
An example of a molecule that follows the octet rule is methane (CH4). In methane, carbon forms four covalent bonds with hydrogen, allowing each atom to achieve a full outer shell of electrons (octet) and satisfy the octet rule.
BCl3 and BEH2 obey the octet rule because Boron and Beryllium are exceptions to the octet rule and can have stable electron configurations with less than 8 electrons. Cl3CF, NO, and SbF5 do not obey the octet rule because they have incomplete or expanded valence shells.