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Assuming a fair coin, the odds of getting four tails in a row are 1 in 16.
1/16
The probability of getting five tails in a row is 1/2^5, or 1 in 32.The probability of getting five heads in a row is 1/2^5, or 1 in 32.Thus, the probability of getting either five heads or five tails in five tosses is 1 in 16.(The caret symbol means "to the power of," as in 2^5 means "2 to the 5th power.")
It is 1/16.
Assuming it is a fair coin, the probability is 1/24 = 1/16.
The probability to get tails once is 1/2 (for a fair coin) The probability to get tails twice = the probability to get it once x the probability to get it a second time The probability to get tails 4 times in a row is (1/2)4=1/16 The probability to get tails n times in a row is (1/2)n=1/2n The same thing is also true for heads (same probability: 1/2 each time)
The probability of getting tails in any one flip is 1/2, so 1/2 x 1/2 x 1/2 x 1/2 = 1/16, or 6.25%
With 4 coins you have 24 (16) possibilities. If we wanted a specific coin to land 'tails' while the others landed 'heads' we would have one possibilty out of 16. Since we don't care which of the coins lands 'tails,' we have four chances in 16 or a 25 percent chance.
The probability of getting all heads is 1/24 = 1/16 The probability of getting all tails is also 1/24 = 1/16 The probability of all heads or all tails is the sum of the two = 1/8
i always thought he went into 4 tails twice once when he was 13 and when he was 16.
It is 1/(2^4) i.e. 1/16 This is because there is 1 in 2 chance of it happening once, and multiply by itself for each successive go.
There are 16 ways that four cars can be parked in a row of four parking spaces. You would multiply the number of cars by the number of spaces.