The nitride ion has a larger negative charge than the fluoride ion and a smaller positive charge in its nucleus, which means a greater repulsion within the electron shells and a lesser attraction to the nucleus.
The fluoride ion is larger than the fluoride atom because it has gained an extra electron, resulting in an increase in electron-electron repulsions, which causes the electron cloud to expand. This increase in electron-electron repulsions leads to a larger ionic radius compared to the atomic radius of the fluoride atom.
The ion of nitrogen (N^3-) is larger than neutral nitrogen (N) due to the addition of three extra electrons, resulting in increased electron repulsion and a larger electron cloud.
Fluorine atom is smaller than fluoride ion because when fluorine gains an electron to form the fluoride ion, it adds an electron in the outermost shell which increases the electron-electron repulsion, causing the electron cloud to expand. This expansion results in the fluoride ion being larger in size compared to the fluorine atom.
The nitrogen ion is larger than the calcium ion because nitrogen is in a higher period (row) than calcium on the periodic table. As you move down a group on the periodic table, the atomic size tends to increase due to the addition of more electron shells. This results in larger ions for elements in higher periods like nitrogen compared to elements in lower periods like calcium.
The radius of a fluoride ion (F-) is larger than that of an oxygen ion (O2-). This is because fluorine has an additional shell of electrons compared to oxygen, leading to increased atomic size and hence larger ionic radius. Additionally, the increase in electron repulsion within the fluoride ion contributes to its larger size compared to the oxide ion.
The fluoride ion is larger than the fluoride atom because it has gained an extra electron, resulting in an increase in electron-electron repulsions, which causes the electron cloud to expand. This increase in electron-electron repulsions leads to a larger ionic radius compared to the atomic radius of the fluoride atom.
The calcium ion is larger than the magnesium ion and so the charge on it is less dense. This makes it less attracted to the fluoride ions
The ion of nitrogen (N^3-) is larger than neutral nitrogen (N) due to the addition of three extra electrons, resulting in increased electron repulsion and a larger electron cloud.
Fluorine atom is smaller than fluoride ion because when fluorine gains an electron to form the fluoride ion, it adds an electron in the outermost shell which increases the electron-electron repulsion, causing the electron cloud to expand. This expansion results in the fluoride ion being larger in size compared to the fluorine atom.
The addition of an electron in Fluorine atom makes it fluoride ion so no of electrons are higher than protons , the extra electron produces repulsive force in outermost shell and electrons move away from nucleus and hence radius of electronic cloud is larger than fluorine atom.
The nitrogen ion is larger than the calcium ion because nitrogen is in a higher period (row) than calcium on the periodic table. As you move down a group on the periodic table, the atomic size tends to increase due to the addition of more electron shells. This results in larger ions for elements in higher periods like nitrogen compared to elements in lower periods like calcium.
Sodium ion (Na+) has a positive charge, while fluoride ion (F-) has a negative charge. Sodium ion is larger in size compared to fluoride ion due to fewer protons and electrons in its structure. Sodium ion is essential for nerve function and muscle contraction, while fluoride ion is commonly found in toothpaste and water for dental health.
The radius of a fluoride ion (F-) is larger than that of an oxygen ion (O2-). This is because fluorine has an additional shell of electrons compared to oxygen, leading to increased atomic size and hence larger ionic radius. Additionally, the increase in electron repulsion within the fluoride ion contributes to its larger size compared to the oxide ion.
The fluoride ion is noted as F- (F minus).
The usual ion form of fluorine is the fluoride ion, which has a charge of -1.
The chloride ion (Cl-) is larger than the oxygen ion (O2-). This is because the chloride ion has more electrons than the oxygen ion, resulting in a larger atomic radius and hence a larger ionic radius.
No, The fluoride ion is a reduced form of fluorine.