Want this question answered?
distance = 1/2 acceleration x time squared; acceleration is 7 m/s/s
Linear Velocity = Initial Velocity (m/s) + Acceleration (m/s2) * t 43.2 km/h
the unit of acceleration is unit length per squared unit time, usually m/s2.
1 way is meters per second squared. [m/s2(the 2 is an exponent)] That is the only way i know. another way is meters per second, per second again [ m/s/s ] ; weird huh? hope that helps
The equation is: http://hyperphysics.phy-astr.gsu.edu/HBASE/imgmec/pend.gif T is the period in seconds, L is pendulum length in cm, g is acceleration of gravity in m/s2. We know on earth the period is 1s when the acceleration of gravity is 9.8m/s2, so the pendulum length is 24.824cm. The acceleration of gravity on the moon is 1.6m/s2. Substitute 24.824cm for L and 1.6 for g and you yield 2.475 seconds. The period is 2.475 seconds.
Acceleration is measured in m/s2 (metres per second squared)
Acceleration is the change in velocity (m/s) divided by time (s), which is the same as meters divided by time in seconds squared (m/s2).
meters per second squared (m/s2)
The formula for the area of a square is s2 (sides squared)
the general form of the units for acceleration are distance per time squared, such as m/s2.
A - 9.8m/s2
distance = 1/2 acceleration x time squared; acceleration is 7 m/s/s
There are 3.28 feet in a meter.The accepted value for Gravitational on earch is 9.8 m/s2convert to feet = 32.2 ft/s2
Metres per second squared (m/s^2 , m/s2 )
Time period of a seconds pendulum is 99.3955111cm at a place where the gravitational acceleration is 9.8m/s2
the unit of acceleration is unit length per squared unit time, usually m/s2.
Linear Velocity = Initial Velocity (m/s) + Acceleration (m/s2) * t 43.2 km/h