The maximum kinetic energy of ejected electrons begins to decrease because excess energy is transferred to surrounding particles as heat or other forms of energy, reducing the energy available for the electrons. This decrease in kinetic energy can be observed as the voltage applied to the system is increased beyond a certain point, leading to a decrease in the maximum energy of the ejected electrons.
The maximum kinetic energy of the emitted electrons is calculated using the formula: (E_k = hf - \phi), where (h) is the Planck constant, (f) is the frequency of the light (speed of light/wavelength), and (\phi) is the work function of molybdenum. Given the wavelength, you can calculate the frequency, then use the work function value for molybdenum to find the maximum kinetic energy of the emitted electrons.
Let the work function of a metal be W. Let C be a constant of the dimension of energy. if Kis the maximum kinetic energy of an electron then.......W=C-K..... (K HERE IS THE ENERGY SUPLIED BY A PHOTON TO THE ELECTRON)
The ball will have maximum kinetic energy at the moment that it is released from the thrower's hand, as it is moving fastest at this point. As the ball travels upward, its kinetic energy will gradually decrease and be converted into potential energy due to the force of gravity acting against it.
The letter showing the ball when it has the maximum kinetic energy is likely the one where the ball is moving the fastest. This is typically when it is at the lowest point in its trajectory due to the maximum potential energy being converted into kinetic energy.
The maximum number of electrons in a single d subshell is 10.
i have the same question on my test haha for me, the answers are: a) The number of electrons ejected per second b) the maximum kinetic energy of the ejected electrons c) the threshold frequency of the ejected electrons d) the time lag between the absorption of blue light and the start of emission of the electrons e) none of these A the number of electrons ejected per second,,,,, correct answer
The maximum kinetic energy of the emitted electrons is calculated using the formula: (E_k = hf - \phi), where (h) is the Planck constant, (f) is the frequency of the light (speed of light/wavelength), and (\phi) is the work function of molybdenum. Given the wavelength, you can calculate the frequency, then use the work function value for molybdenum to find the maximum kinetic energy of the emitted electrons.
Let the work function of a metal be W. Let C be a constant of the dimension of energy. if Kis the maximum kinetic energy of an electron then.......W=C-K..... (K HERE IS THE ENERGY SUPLIED BY A PHOTON TO THE ELECTRON)
At the point where the velocity is the maximum
s contains one orbital with a maximum of 2 electrons p contains three orbitals with a maximum of 6 electrons d contains five orbitals with a maximum of 10 electrons f contains seven orbital with a maximum of 14 electrons
The ball will have maximum kinetic energy at the moment that it is released from the thrower's hand, as it is moving fastest at this point. As the ball travels upward, its kinetic energy will gradually decrease and be converted into potential energy due to the force of gravity acting against it.
A p subshell can contain a maximum of 6 electrons.
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2 electrons is the maximum number for an single orbital.
An s orbital can have a maximum of two electrons.
2 electrons are found in the first electron shell.
There can be a maximum of 10 electrons in a 3d orbital.