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Sodium nitrate (NaNO3) never forms a precipitate when considered with standard rules of solubility. If it was mixed with another solution of the form XA, where X is a cation and N is an anion, no matter what the results were, both results would be soluble.

NaNO3 + XN ---> XNO3 + NaN

By solubility rules, any ionic compound containing a nitrate is always soluble, so the product XNO3 would be soluble no matter what the cation "X" was.

Also by solubility rules, any ionic compound containing a cation from Group I is always soluble. Regardless of what the anion "N" is, the product NaA would always be soluble since sodium (Na) is located in Group I of the Periodic Table of elements.

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