Work = Force x Distance
It can be defined as the work required to stretch or compress the string - the product of force times distance, as an integral, because the force is not constant.
Work can be understood as a transfer of mechanical energy. It is defined as the product of force x distance (if a force is applied over a certain distance); this only applies if force is in the same direction as the movement, and if the force doesn't change. Otherwise, the more precise definition is the integral of: (dot product of force times distance).
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work work
Yes, ft-lb is a unit of work. Work is defined as force times distance. Here you have a force of 1 pound acting through a distance of 1 foot.
Work is defined as force times distance.
Force times distance
Work "W" is defined as the product of force "F" times distance "D": W = FD
It can be defined as the work required to stretch or compress the string - the product of force times distance, as an integral, because the force is not constant.
Work can be understood as a transfer of mechanical energy. It is defined as the product of force x distance (if a force is applied over a certain distance); this only applies if force is in the same direction as the movement, and if the force doesn't change. Otherwise, the more precise definition is the integral of: (dot product of force times distance).
Work is defined as force times distance. If you move something over 2 meters, and you need a force of 15 N for doing that, you'll deliver 30 Joules of work.
force
I actually just took a test over that concept today, work is defined as Force times distance. Work is measured in joules.
< TIMES >You can't add or subtract quantities with different dimensions, like force and distance, speed and volume, etc.
work work
Force is defined as mass times acceleration.Momentum is defined as mass times velocity. Acceleration is defined as the rate of change of velocity. Velocity is defined as the rate of change of location in space.
Yes, ft-lb is a unit of work. Work is defined as force times distance. Here you have a force of 1 pound acting through a distance of 1 foot.