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Answered 2009-07-17 03:31:25

Only if the velocity is constant.

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For the instantaneous value of average velocity, average speed and average velocity are equal.


Average velocity in a direction is calculated as the displacement in that direction divided by the total time taken. As the time interval is reduced, the displacement over that period also reduces and the limiting value of that ratio is the instantaneous velocity.


Velocity is an instantaneous measure. Mathematically, it is the limiting value of the change in the position vector divided by the change in time as the latter tends to zero. Over larger time periods, the average velocity is the total change in the position vector divided by the total change in time. If velocity is constant, the average velocity will be the same as the instantaneous velocity.


The velocity of an object at a particular instant or at a particular point of its path is called instantaneous velocity. In another word, the instantaneous velocity of an object is defined as the limiting value of the average velocity of the object in a small time interval around that instant , when the time interval approaches zero. v = dx/dt , where dx/dt is the differential coefficient of displacement "x" w.r.t. time "t"


this time is basically the instant when an object has a particular velocity(instantaneous velocity). so on the graph draw a line from the particular value of the velocity and then draw a vertical line on time axis to find the time for that velocity.


Never.Average velocity is total displacement (final position minus initial position) divided by the total time: vave = (xf-xi)/tAcceleration is the rate at which your velocity is changing or change in velocity over time: a= (vf-vi)/tThese two quantities may have the same numerical value but will never have the same units.Average velocity for a trip can equal instantaneous velocity at a certain point during the trip, however, at any time during a trip in which the velocity is constant or at half way through the total time of a trip where the acceleration is constant.


Everything has a value assigned to it called instantaneous speed, it is just impossible to measure instantaneous speed, which is why average speed is used. Instantaneous speed can be calculated or inferred, but not measured using any classical methods.


Average velocity equals the average speed if (and only if) the motion is in the same direction. If not, the average speed, being the average of the absolute value of the velocity, will be larger.


coefficient of velocity is 0.97 coefficient of discharge is varied from 0.80 to 0.64 coefficient of contraction is 0.64 thanks to me later .do your assignments


Take the derivative of the function.By plugging a value into the derivative, you can find the instantaneous velocity.By setting the derivative equal to zero and solving, you can find the maximums and/or minimums.Example:Find the instantaneous velocity at x = 3 and find the maximum height.f(x) = -x2 + 4f'(x) = -2xf'(3) = -2*3 = -6So the instantaneous velocity is -6.0 = -2x0 = xSo the maximum height occurs at x = 0f(0) = -02 + 4 = 4So the maximum height is 4.


It is the acceleration at a particular point in time. It is the slope of the velocity vs time curve at a particular point in time.


The average velocity is pretty close to zero. Velocity is a vector, so its average value is the total displacement divided by the total time. Since the racquet probably starts and finishes in the player's bag in the player's home, the average velocity is zero.


This is because reactive power concept is completely different from active(real) power,That is when we talk about active (real) power, we deal with two terms :The average value, and the instantaneous value.Both has significant values; let's say the average value is 5kw, where the instantaneous value maybe 2kw or 6kw, etc...On the otherhand, reactive power has always a Zero average value, and a different significant instantaneous values, but since the instantaneous value is difficult to measure, we always take the maximum instantaneous value of reactive power and deal with it as a textbook terminology (Reactive power) which is symbolized as Q and equals V I sintheta.And for the same reason (difficult to measure instantaneous value ) we easily deal with the average value of the active power other than the instantaneous value.As a brief:(Active power) symbolized P or known sometimes as real power equals V I cos thetarepresents the average value.(Reactive power) symbolized Q equals V I sin theta represents maximum instantaneous value.Someone can ask!Why not to take the maximum instantaneous value of average power such as reactive power as a terminology?Easily , why not to unites the two concepts ?!This is the answer of our main question (Why reactive power is so confusing for engineers?)This is easily because ,there is no useful meaning of using the instantaneous value for the active power, because it is a real produced power goes in one direction from source to load, where the average reactive power is always zero valued, since it goes back and forth in the network, and we are forced to deal with it in some way as an indication value and give it a unique terminology to express it as a fact that we cannot skip.In other words, you cannot compare two different things; apple and banana! Each one has a different taste.I hope that I answered the question, and dislodged some dust about this confusing concept, even I didn't take the boring mathematical path.


This is because reactive power concept is completely different from active(real) power,That is when we talk about active (real) power, we deal with two terms :The average value, and the instantaneous value.Both has significant values; let's say the average value is 5kw, where the instantaneous value maybe 2kw or 6kw, etc...On the otherhand, reactive power has always a Zero average value, and a different significant instantaneous values, but since the instantaneous value is difficult to measure, we always take the maximum instantaneous value of reactive power and deal with it as a textbook terminology (Reactive power) which is symbolized as Q and equals V I sintheta.And for the same reason (difficult to measure instantaneous value ) we easily deal with the average value of the active power other than the instantaneous value.As a brief:(Active power) symbolized P or known sometimes as real power equals V I cos thetarepresents the average value.(Reactive power) symbolized Q equals V I sin theta represents maximum instantaneous value.Someone can ask!Why not to take the maximum instantaneous value of active power such as reactive power as a terminology?Easily , why not to unites the two concepts ?!This is the answer of our main question (Why reactive power is so confusing to understand?)This is easily because ,there is no useful meaning of using the instantaneous value for the active power, because it is a real produced power goes in one direction from source to load, where the average reactive power is always zero valued, since it goes back and forth in the network, and we are forced to deal with it in some way as an indication value and give it a unique terminology to express it as a fact that we cannot skip.In other words, you cannot compare two different things; apple and banana! Each one has a different taste.I hope that I answered the question, and dislodged some dust about this confusing concept, even I didn't take the boring mathematical path.


954 / 2.8 = 340.71428571428571428571428571429About 340 time units(I would have said 341 if there had been three significant figures in the velocity value)


Yes usually and no rarely, velocity is defined as a vector, having both a direction and a magnitude (which is speed in the case of velocity). For instance 100 mph (speed) east (0o) (direction). In this form it is easy to see that the magnitude is 100 mph but mathematically to determine the magnitude of a vector you would divide the vector by its direction. 100 mph 0o / 0o = 100 mph Average speed and average velocity share the same relationship as instantaneous speed and instantaneous velocity so divide out the average direction from your average velocity to determine your average speed. If this is over a time period and you know the beginning and ending places in space your averages will simply be the difference from the starting to the ending places. So yes so long as you define speed to actually be the magnitude of the vector. However, if speed is taken without direction over time it may become something different. If an object travels along a vector with a negative magnitude its speed will not be negative but its vector magnitude will. Ex: A car travelling in reverse still has a positive speed but a compass will show it to be heading in the opposite direction of travel, a negative vector value...


Of course, since the instantaneous velocity indicates the velocity at a certain moment in time it does not describe the change in this velocity a moment from the stated instance, which is the acceleration. Therefore, the initial velocity can be zero and still experience an acceleration since the velocity may change in the next instance. The instantaneous velocity of an object is merely the derivative of the position function, the acceleration which is the 2nd derivative of position. Therefore acceleration is first derivative of velocity, thus, the slope of the velocity function may be non zero while the function value at the given time may be zero. For instance consider a simple parabola, y = t2, as the position function, this is obvious from the non linear nature of the graph that there is an acceleration experienced. The velocity function is, by taking the derivative, v = 2t, which is a linear function, stating a constantly changing velocity. The acceleration, differential once again, is a = 2. Thus, we have found that the acceleration at every point in time the acceleration is 2. Looking at the velocity function, it is obvious that there is a zero at t = 0, while at all time the acceleration is 2. Thus, this is an example showing that a function value in a function does not describe its immediate changes from this current point to the next, thus knowing the instantaneous velocity of an object does not give any information about its acceleration unless a change in this velocity is given.


Instantaneous speed is your speed in a given moment. The speedometer in your car and the radar gun that cops use both give a value in instantaneous speed. The disctinction here is to not confuse instantaneous speed with average speed, which is calculated over a set distance. To calculate average speed (V) you need to divide the distance travelled (D) by the time of travel (T). V= D/T


If you are actually in your car, check the spedometer. That will tell you your instantaneous velocity; that is, distance traveled per second.If this is a calculus question and you are given the function of your position with respect to time, simply take the derivative of your function and evaluate your derivative at the time at which you would like to determine your instantaneous velocity.Alternatively and more unlikely, you can integrate your acceleration function and solve for your antiderivative based on an initial value given by the context of the problem.


The velocity. This is true because velocity is a vector value meaning it has magnitude and direction. If is had just a magnitude, then it would be a scalar value.


Yes usually and no rarely, velocity is defined as a vector, having both a direction and a magnitude (which is speed in the case of velocity). For instance 100 mph (speed) east (0o) (direction). In this form it is easy to see that the magnitude is 100 mph but mathematically to determine the magnitude of a vector you would divide the vector by its direction. 100 mph 0o / 0o = 100 mph Average speed and average velocity share the same relationship as instantaneous speed and instantaneous velocity so divide out the average direction from your average velocity to determine your average speed. If this is over a time period and you know the beginning and ending places in space your averages will simply be the difference from the starting to the ending places. So yes so long as you define speed to actually be the magnitude of the vector. However, if speed is taken without direction over time it may become something different. If an object travels along a vector with a negative magnitude its speed will not be negative but its vector magnitude will. Ex: A car travelling in reverse still has a positive speed but a compass will show it to be heading in the opposite direction of travel, a negative vector value...


The dependent value on a velocity-time graph is velocity.


Velocity is a vector. The magnitude of the velocity - its absolute value - is its speed.


the approximate value of orbital velocity is about 8km/hr.


If the mass is doubled and the velocity is also doubled,then the momentum is four times its original value.



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