How do you Write a program to read natural numbers from a keyboard Find the largest and the smallest number?

Answer 1

This sounds like a homework assignment, so I will give you some pseudo code instead of straight C code.

[code]

OPEN FILE FOR READING

IF NOT END OF FILE THEN

min = READ FILE INPUT

max = min

ENDIF

WHILE NOT END OF FILE

x = READ FILE INPUT

IF x < min THEN

min = x

ENDIF

IF x > max THEN

max = x

ENDIF

ENDWHILE

CLOSE FILE

[/code]

If you are using C, then you will need to use fopen(), scanf(), fclose() and maybe feof(). If you are using C++ then you can use fstream, must like you would use cin, except that you have to open the stream, check for end of file and close it.

Answer 2

int getGreaterNumber(int num1, int num2)

{

if (num1 > num2)

{

return num1;

}

else

{

return num2;

}

}

Answer 3

int
getLargest(int array[], const int asize) {
int largest = array[0];

int i;

for (i = 1; i < asize; ++i) {

if (largest < array[i])

largest = array[i];

}

return largest;

}

Answer 4

//using arrays// #include<stdio.h>

#include<conio.h>

void main()

{

int x[10],i;

clrscr();

printf("enter the values:");

for(i=0;i<10;i++)

scanf("%d",&x[i]);

big=x[0];

for(i=0;i<10;i++)

{

if(big<x[i])

{

big=x[i];

}

}

printf("big value =%d",big);

getch();

}

Answer 5

import java.io.*;

class largesmall

{

public static void main(String[] args)

{

int arr[] = { 17, 23,31,45,36,7,32,67,54,30};

int l=0; int i; int s=arr[0];

for(i=0;i<10;i++)

{

if(arr[i]>=l)

{

l=arr[i];

}

}

for(i=0;i<10;i++)

{

if(arr[i]<=s)

{

s=arr[i];

}

}

System.out.println("Largest Value : " +l+ "");

System.out.println("Smallest Value : " +s+ "");

}

}

/* Ashish Ranjan

Jaypee Institute of Information Technology*/

Answer 6

Biggest = 0

For N = 1 to 10

If Number(N) > Biggest then Biggest = Number(N)

Next N

Print "The biggest of the ten numbers is "; Biggest

Print "That was fun. Thanks for playing."

END

Answer 7

Define two variables for the largest and smallest number. I'll call them "smallest" and "largest" for the following explanation. Read the first number; assume that it is both the largest and the smallest. That is, copy its value to both variables. Read additional values in a loop; for every number:

* If it is less than your variable "smallest", copy its value to variable "smallest".

* If it is larger than your variable "largest", copy its value to variable "largest".

Answer 8

In Java

int a, b, c; // assign these values elsewhere

int max = Math.max(a, Math.max(b, c));

int min = Math.min(a, Math.min(b, c));