Relative to the bus, you are moving towards the back. If your walking speed is slower than the speed of the moving bus (which it usually will be) then your motion relative to a point on the ground will be moving in the direction of the moving bus, but slower by the speed at which you are walking.
If the person walking has a velocity lower than the bus, they will be moving forward relative to a static point on the ground. They will however be moving backward relative to a static point on the bus.
From the point of reference of a person on the bus, the bus
is generally at rest, but with some frequent jolts up, down,
forward and backward, left and right.
i am just a loco kid okay ........................anyways you should know!
The person riding on the bus may feel the bus is at rest. But there may be frequent jolts up and down.
Zero.
To move an object forward from rest the thrust of forward force must be greater than the drag acting in the opposite direction. In order to keep moving at a constant velocity the forward force must equal the drag.
The velocity of the person is the velocity of the speeding train plus the velocity of the jump out. this gives a resultant velocity with a forward component in the direction of the train's motion.
The road is the horizontal force on the car. The tires push on the road which is the action and the road pushes forward on the tires which is the reaction.
Forward it is the same as the plane that he/she was jumping off. Downward it is up to 300-350 kph.
1. force that moves a car forward is the friction force between the tires and the road (ignoring what is going on mechanically in the car) 2. if the car is travelling at constant velocity, net force is zero - forces pushing car forward are equal to forces pushing car back
Zero.
To move an object forward from rest the thrust of forward force must be greater than the drag acting in the opposite direction. In order to keep moving at a constant velocity the forward force must equal the drag.
The velocity of the person is the velocity of the speeding train plus the velocity of the jump out. this gives a resultant velocity with a forward component in the direction of the train's motion.
If you have the CV ( constant velocity joint ) in front of you it will be without any play in the bearings, the bearings will not be cracked or loose. the splines on each end will be without burs. If still in the vehicle you will notice a grind or clunk (both in forward and reverse), from the front of the car, more so under acceleration
Kind of, yes. It's a balance between orbital velocity, which is the high speed relative to the ground, and gravity, which is the force keeping the object in orbit.
40 newtons. give the explanation of this
No. It depends on what other forces are acting on the object.
Describe left forward stance in your own words ?
left, right, forward, backward, forward, up and down
The road is the horizontal force on the car. The tires push on the road which is the action and the road pushes forward on the tires which is the reaction.
Forward it is the same as the plane that he/she was jumping off. Downward it is up to 300-350 kph.