The letters can be rearranged to form the word "counter."
There is no 8 letter word that can be made from the letters in "in and out". Words that can be made from those letters are:aadaidanandantataudioauditauntautodauntdindintdodondonnadonutdotdunduoIidininnintoioniotaitnationnitnonodnotnounnunnutoatonouttadtantintotoadtontunaundounionunitunto
The word "house" has 5 distinct letters. The number of ways to arrange these letters is calculated using the factorial of the number of letters, which is 5! (5 factorial). This equals 5 × 4 × 3 × 2 × 1 = 120. Therefore, there are 120 different ways to arrange the letters in the word "house."
Since no letters are repeated in the word prime, you can arrange the letters in the word prime 5! ways, or 120 ways.
3*2*1 = 6 ways.
The word "onomatopoeia" has 11 letters, with 6 vowels and 5 consonants. Therefore, there are 11!/(6!5!) = 33,120 ways to arrange the word "onomatopoeia".
If you have three DIFFERENT letters, you can arrange them in 3! = 1 x 2 x 3 = 6 different ways.
If all the letters of the word are different then the answer is 8! = 8*7*6* 5 *4*3*2*1 = 40320.
You can arrange the letters in "the letters in the word Hornet", in 7,480,328,917,501,440,000 different ways. There are 25 letter in all, but there are 2 each of n and o, 3 each of h and r, 5 each of e and t. So the number of ways is 25!/[2!*2!*3!*3!*5!*5!] where n! = 1*2*3*...*n
The word "MATH" consists of 4 unique letters. The number of different arrangements of these letters can be calculated using the factorial of the number of letters, which is 4!. Therefore, the total number of arrangements is 4! = 4 × 3 × 2 × 1 = 24. Thus, there are 24 different ways to arrange the letters in the word "MATH."
6! = 6 x 5 x 4 x 3 x 2 x 1 = 720 ways
Consider "qu" to be a single letter and then you have 4 letters to arrange in 4 slots. For the first slot you have 4 choices, the next you have 3, and so on. So the number of ways is 4*3*2*1 = 24.
3! = 1 x 2 x 3 = 6 ways.