If it is a fair coin, the probability is exactly 50%. The coin has no memory of what it did in the last flip. ■
The probability is 5/16.
If you have tossed a fair, balanced coin 100 times and it has landed on HEADS 100 consecutive times, the probability of tossing HEADS on the next toss is 50%.
The empirical probability can only be determined by carrying out the experiment a very large number of times. Otherwise it would be the theoretical probability.
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It depends on how many times you toss it.
1/2 chance of getting heads or tails 5 times 1/10
The probability that a coin flipped four consecutive times will always land on heads is 1 in 16. Since the events are sequentially unrelated, take the probability of heads in 1 try, 0.5, and raise that to the power of 4... 1 in 24 = 1 in 16
It is (1/2)3 = 1/8 or 0.125
Answer this Question : Probability of getting 10 heads in a row is(1/2)^10 = 1/1024 = 0.000976 or 0.098 %
There are 23 or 8 possibilities; one is HHH. So, probability of HHH is 1/8 or 0.125.
The probability is 0.25.Look at it this way--if you toss a coin twice, there are four equally-probable outcomes:tails, tailstails, headsheads, tailsheads, headsSo the probability of heads twice in a row is one in four, or 25%.the chance of tossing heads is 1/2 (50%) The chance of tossing the next heads is 1/2 (50%) 1/2 x 1/2 = 1/4 (25%)
75 over 2^23 (2 times itself 23 times, 2x2x2x2x2 etc...)
The probability of tossing a coin 9 times and getting at least one tail is: P(9 times, at least 1 tail) = 1 - P(9 heads) = 1 - (0.50)9 = 0.9980... ≈ 99.8%
Each toss has a 1/2 probability of getting heads. Each toss is an independent event. So three heads in a row (heads AND heads AND heads) would have a probability of:1/2 * 1/2 * 1/2 = (1/2)^3 = 1/(2^3) = 1/8 = 12.5%
First event is to roll a 3 or 6 on a die, which gives you a probability of 2 out of 6. Second event is tossing a heads on a coin, so a probability of 1 out of 2. Since both chances are not related, you can multiply both chances: 2/6 times 1/2 = 1/6 = 0,166666...
If you look at the as the probability of getting 1 or more tail in 4 coin tosses, you would then calculate the probability of tossing 4 heads in a row and subracting that from 1. The probability fo tossing 4 heads is 1/2 * 1/2 * 1/2 * 1/2 = 1/16. 1 - 1/16 = 15/16.
It is 17C5*(1/16)5*(15/16)12 = 0.00272 approx.
The probability is 0.998
If you continue tossing the coin forever, it is effectively a certainty. So probability = 1 If you toss it only 9 times, it is (1/2)9 = 1/512 = 0.00195 (approx)
Each time you toss the die the probability of rolling an even number is 3 out of 6 or 1/2. So, the probability of tossing three consecutive even numbers is (1/2)3 = 1/8 = 0.125, which is one chance in eight.