How does increasing the amount of stored energy affect the amount of kinetic energy when an object is released?

Answer 1

The "stored energy", or potential energy, will be converted to kinetic energy.

Example:

Let U = gravitational potential energy, K = kinetic energy

U = mgh, where m is mass, g is theaccelerationdue to gravity, h is the height

(there are other types of potential energy, but this is the most common example)

K = 1/2mv2, where v is velocity

Set U equal to K, because that potential energy will be converted to kinetic energy, minus any other factors that "steal" energy (i.e., friction):

U = K

mgh = 1/2mv2 <-- masses cancel

gh = 1/2v2

The left side of the equation represents stored energy. The right side represents kinetic energy. If we increase the left side by a factor of A, we must increase the right side by a factor of A as well (it's just an algebraic step):

A(gh) = A(1/2v2)

So it should be visible, that if you if you increase potential energy, you also increase kinetic energy (by the same proportion).

Answer 2

Some of the available energy is converted to heat by friction, so the amount of useful work done is reduced by friction.

Answer 3

The Kinetic Energy Will Decrease