Ba(NO3)2 + 2NaOH → Ba(OH)2 + 2NaNO3
Barium nitrate + sodium hydroxide → barium hydroxide + sodium nitrate
Ba(OH)2 + Na2CO3 >> BaCO3 + 2NaOH
2KOH + Ba(NO3)2 -----> 2KNO3 + Ba(OH)2
The balanced equation is: Ca(NO3)2 + 2NaOH → Ca(OH)2 + 2NaNO3
Al(NO3)3 + 3 NaOH --> Al(OH)3 + 3 NaNO3
Cu(NO3)2 + 2NaOH >> Cu(OH)2 + 2NaNO3
You get Iron (III) Hydroxide and Sodium Nitrate. It is a double displacement chemical reaction...
The chemical reaction is: NH4NO3 + NaOH -----→ NH3 + H2O + NaNO3
The chemical reaction is: NH4NO3 + NaOH ---------→ NH3 + H2O + NaNO3
2KOH + Ba(NO3)2 -----> 2KNO3 + Ba(OH)2
The chemical reaction is: NH4NO3 + NaOH -----→ NH3 + H2O + NaNO3
The balanced equation is: Ca(NO3)2 + 2NaOH → Ca(OH)2 + 2NaNO3
Ca(NO3)2 + 2NaOH >> Ca(OH)2 + 2NaNO3
Fe(NO3)2 + 2NaOH-->Fe(OH)2 + 2NaNO3 (Assuming Fe is Fe (II))
in:chemestry
No. It is a chemical change (chemical reaction) in which the products are different from the reactants. The balanced chemical equation is Cu(NO3)2+2NH4OH-->Cu(OH)2+2NH4NO3, which means one mole of copper(II) nitrate plus two moles of ammonium hydroxide produce one mole of copper(II) hydroxide plus two moles of ammonium nitrate.
Your balanced chemical equation for this double replacement reaction would be: Cu(NO3)2 + 2KOH ----> Cu(OH)2 + 2KNO3 Therefore, you would end up with copper II hydroxide and potassium nitrate.
Word equation: Sodium Hydroxide + Calcium Nitrate --> Calcium Hydroxide + Sodium Nitrate Chemical equation: Ca(NO3)2 + 2NaOH --> Ca(OH)2 + 2NaNo3
Al(NO3)3 + 3 NaOH --> Al(OH)3 + 3 NaNO3