H2SO4 is a strong acid commonly known as sulfuric acid. NaOH is a strong base commonly known as sodium hydroxide. When the two are mixed at a ratio of 1mol of H2SO4 to 2 mols of NaOH, a neutralization reaction occurs.
The balanced chemical equation between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O This equation shows that 2 moles of KOH react with 1 mole of H2SO4 to produce 1 mole of K2SO4 and 2 moles of water.
The chemical equation is not balanced. A balanced equation would be: KOH + H2SO4 -> KHSO4 + H2O
The chemical equation for the reaction between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2KOH + H2SO4 → K2SO4 + 2H2O.
First, calculate the number of moles of H2SO4: Moles H2SO4 = volume (L) * concentration (mol/L) Next, use the balanced equation to determine the mole ratio between H2SO4 and KOH. The balanced equation is H2SO4 + 2KOH -> K2SO4 + 2H2O. Then, calculate the molarity of KOH: Molarity KOH = moles of KOH / volume of KOH solution (L)
The balanced chemical equation for the neutralization reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) to produce potassium sulfate and water is: H2SO4 + 2KOH → K2SO4 + 2H2O
The balanced chemical equation between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O This equation shows that 2 moles of KOH react with 1 mole of H2SO4 to produce 1 mole of K2SO4 and 2 moles of water.
The chemical equation is not balanced. A balanced equation would be: KOH + H2SO4 -> KHSO4 + H2O
The chemical equation for the reaction between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2KOH + H2SO4 → K2SO4 + 2H2O.
First, calculate the number of moles of H2SO4: Moles H2SO4 = volume (L) * concentration (mol/L) Next, use the balanced equation to determine the mole ratio between H2SO4 and KOH. The balanced equation is H2SO4 + 2KOH -> K2SO4 + 2H2O. Then, calculate the molarity of KOH: Molarity KOH = moles of KOH / volume of KOH solution (L)
The balanced chemical equation for the neutralization reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) to produce potassium sulfate and water is: H2SO4 + 2KOH → K2SO4 + 2H2O
The balanced chemical equation for the reaction is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O From the equation, it can be seen that 2 moles of KOH react with 1 mole of H2SO4. Calculate the moles of H2SO4 (2.70 g / molar mass of H2SO4) and then use the mole ratio to find the moles of KOH required. Finally, convert the moles of KOH to mass (moles of KOH x molar mass of KOH) to get the required mass of KOH.
An example is:2 KOH + H2SO4 = K2SO4 + 2 H2O
To balance the chemical equation FeO + H2SO4 → Fe2(SO4)3 + H2O, you would need to adjust the coefficients of the compounds. One balanced equation would be 3FeO + H2SO4 → Fe2(SO4)3 + H2O.
Together they make ammonium sulfate and water.
The equation is:2 KOH + H2SO4 = K2SO4 + 2 H2O
The balanced equation is Ca(OH)2 + H2SO4 → CaSO4 + 2H2O.
To balance the reaction between NaOH and H2SO4, you first write out the unbalanced equation: NaOH + H2SO4 -> Na2SO4 + H2O. To balance it, you need to ensure the same number of atoms of each element on both sides of the equation by adjusting the coefficients. In this case, you would need to put a coefficient of 2 in front of NaOH to balance the equation: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.