How do make a 5.25N sulfuric acid solution from concentrated sulfuric acid solution?

Answer 1

con.H2SO4 is 98%(v/v)

con H2So4 is 36.8 N

To prepare 10 N , It has be diluted 14.72 times with water

Answer 2

• con.H2SO4 is 98%(v/v)
• ie 980ml/litre.
• or 980X1.84(specific gravity of H2So4)
• ie wt/litre is 1803.2
• Normality= wt per litre/ Eq.wt
• ie 1803.2/49=36.8 N
• Hence con H2So4 is 36.8 N
• To prepare 5 N , It has be diluted 7.36 times with water

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Answer 3

0.5 N H2SO4 is equivalent to 0.25 M H2SO4 because normality (N) is based on equivalents and H2SO4 has 2 equivalents (2 H+ per mole H2SO4). Thus, calculate how to prepare 0.25 M H2SO4.
0.25 moles/L x 98 g/mole = 24.5 g H2SO4 in 1 liter of solution = 0.25 M = 0.5 N

Answer 4

To make a 5.25N sulfuric acid solution from concentrated sulfuric acid (98%), you would need to dilute the concentrated sulfuric acid with water in the correct proportions. Calculate the volume of concentrated sulfuric acid needed using the formula C1V1 = C2V2, where C1 is the concentration of the concentrated acid (98%), V1 is the volume of concentrated acid needed, C2 is the desired concentration (5.25N), and V2 is the final volume of the solution. Add the calculated volume of concentrated acid to a container and carefully add water to reach the final volume while stirring to mix thoroughly. Remember to always add acid to water and not the other way around for safety.

Answer 5

how to prepare 5n sulfuric acid from stock soloution

Answer 6

how 2.5N H2SO4 prepared from concentrated H2SO4

Answer 7

31 ml to 200ml