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First write the balanced chemical equation:

2 Mg + O2 --> 2 MgO.

Now solve for the theoretical amount of MgO formed:

(82.56 g Mg / 1) * (1 mol Mg / 24.305 g Mg) * (2 mol MgO / 2 mol Mg) * (40.3044 g MgO / 1 mol MgO) = 136.9 g MgO.

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