Vanadium forms four different oxides in which the percent by mass of vanadium is respectively 76 percent 68 percent 61 percent and 56 percent what is thire formulas?

Answer 1

Mass V = 76 g

moles V = 76/ 51 g/mol=1.5

moles O = 100 - 76/ 16= 1.5

VO

Moles V = 68/51 = 1.3

Moles O = 100-68/16=2

1.3/1.3 = 1 =>V

2/1.3=1.5 =>O

multiply by 2 to get whole numbers

V2O3

moles V = 61/51=1.2

moles O = 100-61/16=2.4

VO2

moles V = 56/51=1.1

moles O= 100-56/16= 2.75

1.1/1.1= 1 => V

2.75/1.1= 2.5 =>O

to get whole numbers multiply by 2

V2O5

Answer 2

The oxides with percentages of 76%, 68%, 61%, and 56% by mass of vanadium correspond to the formulas V2O5, V2O4, VO2, and VO respectively.