Many organic compounds have this chemical formula; see the link below.
C4H10 is the molecular formula for butane, as it represents the actual number of atoms of each element in a single molecule of the compound. The empirical formula for butane would be CH5, as it shows the simplest whole number ratio of atoms present in the compound.
The formula is 2 x C2H5 = C4H10. :)
No, C4H10 is not an acid. It is a hydrocarbon known as butane, which is a colorless, odorless gas commonly used as fuel.
C4H10 is the saturated hydrocarbon. It is a type of alkane called butane, characterized by single carbon-carbon bonds and maximum number of hydrogen atoms.
C4H10 is a compound. It is the chemical formula for butane, which is a hydrocarbon that consists of carbon and hydrogen atoms bonded together.
C4H10 is the molecular formula for butane, as it represents the actual number of atoms of each element in a single molecule of the compound. The empirical formula for butane would be CH5, as it shows the simplest whole number ratio of atoms present in the compound.
C4H10(g) is about -126 kJ/mol C4H10(l) is about -147 kJ/mol
1 mole C4H10 = 58.1222g = 6.022 x 1023 molecules 11.7g C4H10 x 6.022 x 1023 molecules/58.1222g = 1.21 x 1023 molecules C4H10
The correct molecular formula for methylpropane is C4H10.
The formula is 2 x C2H5 = C4H10. :)
The chemical formula for butanal is CH3CH2CH2CHO.
No, C4H10 is not an acid. It is a hydrocarbon known as butane, which is a colorless, odorless gas commonly used as fuel.
C4H10 is the saturated hydrocarbon. It is a type of alkane called butane, characterized by single carbon-carbon bonds and maximum number of hydrogen atoms.
To find the mass of O2 that will react with 400 g of C4H10, first calculate the moles of C4H10 using its molar mass. Then, using the balanced chemical equation for the reaction between C4H10 and O2, determine the mole ratio between C4H10 and O2. Finally, convert the moles of C4H10 to moles of O2 and then to grams of O2 using the molar mass of O2.
The balanced equation for the reaction of tetracarbon decahydride (C4H10) and oxygen (O2) is: C4H10 + 6.5 O2 → 4 CO2 + 5 H2O.
C4h10
Butane