What is electron configuration for Ti?

Answer 1

[Ar]4s23d2

Answer 2

Titanium --------------------------> Ti4+ + 4e-

[1s2, 2s22p6, 3s23p6] 3d2, 4s2 --->[1s2, 2s22p6, 3s23p6] + 4 electrons (from 3d and 4s orbital)

Ti4+ is iso-electronic to Argon [1s2, 2s22p6, 3s23p6 ], the foregoing noble gas.

Answer 3

1s2 2s2 2p6 3s2 3p6 4s2 3d2

OR

[Ar] 4s2 3d2

Answer 4

The base expression (ground state; Ti0) is [Ar]3d24s2 so removal of 4 electrons to get the oxidation state of 4+ would result in the configuration of [Ar]

Answer 5

[Ar] it would lose 2 electrons from 4s and then 2 electrons from 3d

Answer 6

The base expression (ground state; Ti0) is [Ar]3d24s2 so removal of 2 electrons to get the oxidation state of 2+ would result in the configuration of [Ar] 3d2.

Answer 7

The electron configuration of titanium is [Ar]3d24s2.

Answer 8

The electron configuration for titanium (Ti) is 1s2 2s2 2p6 3s2 3p6 3d2 4s2.

Answer 9

[Ar] 4s23d2