NO!!! It is a neutralisation reaction. Reason it produces water (pH =7)
KOH + HBr = KBr + H2O
KBr (Potassium bromide) is a (chemical) salt.
Remember the the empirical acid equations.
Acid + Alkali = Salt + water
Acid + Base = Salt + water
Acid + metal = Salt + hydrogen
Acid + carbonate = Salt + Water + Carbon dioxide.
NB
Acid formulas are always writen as 'HA'. Where 'A' is the anion.
Alkali formulkas are always written as 'MOH'. Where 'M' is the metal cation.
NNB Notice the positions of the 'H' in these formulas.
The chemical equation is not balanced. A balanced equation would be: KOH + H2SO4 -> KHSO4 + H2O
The balanced equation for potassium hydroxide (KOH) and hydrofluoric acid (HF) is: KOH + HF → KF + H2O.
The balanced equation for the reaction between hydrochloric acid (HCl) and potassium hydroxide (KOH) is: HCl + KOH -> KCl + H2O
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
HC2H3O2(aq) + KOH(aq) -> H2O(l) + KC2H3O2(aq)It's already balanced, since there are two acetates, two Hydrogens on each side, and 1 oxygen on both sides :)
The chemical equation is not balanced. A balanced equation would be: KOH + H2SO4 -> KHSO4 + H2O
The balanced equation for potassium hydroxide (KOH) and hydrofluoric acid (HF) is: KOH + HF → KF + H2O.
The balanced equation for the reaction between hydrochloric acid (HCl) and potassium hydroxide (KOH) is: HCl + KOH -> KCl + H2O
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
HC2H3O2(aq) + KOH(aq) -> H2O(l) + KC2H3O2(aq)It's already balanced, since there are two acetates, two Hydrogens on each side, and 1 oxygen on both sides :)
Balanced :2 K + 2 H2O ----> 2 KOH + H2
Balanced:2 KOH + SO3 ----> K2SO4 + H2O
The balanced chemical equation for potassium hydroxide (KOH) reacting with carbon dioxide (CO2) to form potassium carbonate (K2CO3) and water (H2O) is: 2 KOH + CO2 → K2CO3 + H2O
I assume KOH is limiting. Balanced equation. KOH + HCl -> KCl + H2O 0.400 moles KOH (1 mole H2O/1 mole KOH)(18.016 grams/1 mole H2O) = 7.21 grams water produced =====================
The balanced chemical equation for acetic acid (HC2H3O2) in vinegar reacting with potassium hydroxide (KOH) is: HC2H3O2 + KOH -> KC2H3O2 + H2O This balanced equation shows that one molecule of acetic acid reacts with one molecule of potassium hydroxide to form one molecule of potassium acetate and one molecule of water.
CH3COOH + KOH = CH3COOK + H2O
An example is:2 KOH + H2SO4 = K2SO4 + 2 H2O