The answer is 144,007 g for the anhydrous aluminium chloride.
To find the molar mass of the nonelectrolyte compound, we need to use the formula: Molar mass (mass of compound / moles of compound) First, we need to find the moles of the compound by using the formula: moles mass / molar mass Given that the mass of the compound is 4.305 g and it is dissolved in 105 g of water, we can calculate the moles of the compound. Next, we can find the molar mass of the compound by rearranging the formula: Molar mass mass / moles By plugging in the values, we can calculate the molar mass of the nonelectrolyte compound.
First, we calculate the molar mass of MgCl2, which is 95.21 g/mol. Then, we divide the given mass by the molar mass to determine the number of moles of MgCl2. So, 105 g of MgCl2 contains approximately 1.10 moles of MgCl2.
To find the number of moles of AlCN3 in 229 g of the compound, you first need to determine the molar mass of AlCN3. The molar mass of AlCN3 is 144.99 g/mol. Divide the given mass of 229 g by the molar mass to find the number of moles. Moles = Mass / Molar mass Moles = 229 g / 144.99 g/mol Moles ≈ 1.58 moles
The total mass of the solution is 105 grams, which is the sum of the mass of the salt (5 grams) and the mass of the water (100 grams). The mass of the solute (salt) and the solvent (water) are additive in a solution.
The balanced chemical equation for the combustion of methanol is: 2CH3OH + 3O2 -> 2CO2 + 4H2O From the equation, 2 moles of methanol produce 2 moles of CO2. One mole of CH3OH has a molar mass of 32.04 g, and one mole of CO2 has a molar mass of 44.01 g. First, find the number of moles of methanol in 805 g. Then, use the stoichiometry of the balanced equation to calculate the mass of CO2 produced.
To calculate the mass of nickel in milligrams from moles: Find the molar mass of nickel from the periodic table: 58.69 g/mol. Convert moles to grams given mole quantity x molar mass. Convert grams to milligrams (1 g = 1000 mg) to find the mass in milligrams.
1.54 x 105 mg
To find the molar mass of the nonelectrolyte compound, we need to use the formula: Molar mass (mass of compound / moles of compound) First, we need to find the moles of the compound by using the formula: moles mass / molar mass Given that the mass of the compound is 4.305 g and it is dissolved in 105 g of water, we can calculate the moles of the compound. Next, we can find the molar mass of the compound by rearranging the formula: Molar mass mass / moles By plugging in the values, we can calculate the molar mass of the nonelectrolyte compound.
Density is grams per cm3. 615/105 = 5.86 g/cm3
First, we calculate the molar mass of MgCl2, which is 95.21 g/mol. Then, we divide the given mass by the molar mass to determine the number of moles of MgCl2. So, 105 g of MgCl2 contains approximately 1.10 moles of MgCl2.
To find the number of moles of AlCN3 in 229 g of the compound, you first need to determine the molar mass of AlCN3. The molar mass of AlCN3 is 144.99 g/mol. Divide the given mass of 229 g by the molar mass to find the number of moles. Moles = Mass / Molar mass Moles = 229 g / 144.99 g/mol Moles ≈ 1.58 moles
105 pounds is 47,627.2 grams.
The density is about 5.86 g/cm3
105 grams is about 0.231 pounds.
9.375 lbs (on earth?) or mass is4,252.42847 grams
Assuming that the reaction is combustion, the balanced reaction equationwould be2 C4H10 +13 O2 ->8 CO2 +10 H2O. This shows that each mole of O2 would produce 8/13 mole of CO2. 105 grams of O2 corresponds to [105/(2 exact)(15.9994)] or about 3.281 moles of O2. or (8/13)(3.281) or 2.02 moles of carbon dioxide, to the justified number of significant digits.
The total mass of the solution is 105 grams, which is the sum of the mass of the salt (5 grams) and the mass of the water (100 grams). The mass of the solute (salt) and the solvent (water) are additive in a solution.