HC2H3O2(aq) + KOH(aq) -> H2O(l) + KC2H3O2(aq)
It's already balanced, since there are two acetates, two Hydrogens on each side, and 1 oxygen on both sides :)
This equation is Al2O3 + 6 HCl = 2 AlCl3 + 3 H2O.
The balanced chemical equation for the reaction is: PCl3 + 3H2O → H3PO3 + 3HCl
Hydrochloric acid doesn't react with water; they form a solution.
The reaction between NaOH and HCl produces NaCl (sodium chloride) and H2O (water). The balanced chemical equation is: NaOH + HCl → NaCl + H2O.
The balanced equation for hydrochloric acid (HCl) with ammonium hydroxide (NH4OH) is: HCl + NH4OH → NH4Cl + H2O.
The balanced equation for BaCO3 + 2HI is BaCO3 + 2HI → BaI2 + H2O + CO2.
This equation is Al2O3 + 6 HCl = 2 AlCl3 + 3 H2O.
The balanced chemical equation for the reaction is: PCl3 + 3H2O → H3PO3 + 3HCl
Hydrochloric acid doesn't react with water; they form a solution.
The reaction between NaOH and HCl produces NaCl (sodium chloride) and H2O (water). The balanced chemical equation is: NaOH + HCl → NaCl + H2O.
This equation is HCl + NaOH -> NaCl + H2O.
The balanced equation for hydrochloric acid (HCl) with ammonium hydroxide (NH4OH) is: HCl + NH4OH → NH4Cl + H2O.
The balanced equation is 2HCl + K2O -> H2O + 2KCl.
This equation is NaClO (aq) + 2 HCl (aq) = NaCl (aq) + Cl2 + H2O.
HCl + NaOH = H2O + NaCl is already balanced.
HCl + NaOH --> NaCl + H2O is balanced as you wrote it.But, since sodium is always soluble in water at temperatures below the boiling point of the solution, the net ionic equation for the reaction at temperatures lower than the boiling point would actually be: HCl + OH- --> Cl- + H2OOr, if the hydrochloric acid was already in solution, then simplyH+ + OH- ---> H2O
The balanced equation for the reaction between hydrochloric acid (HCl) and calcium carbonate (CaCO3) is: 2HCl + CaCO3 -> CaCl2 + H2O + CO2.