This is a double displacement reaction, also known as a metathesis reaction. In this reaction, ions in the reactants exchange partners to form new compounds.
MgSO4 + Na2CO3 -> MgCO3 + Na2SO4 Mg2+ (aq) + SO42- (aq) + 2Na+ (aq) + CO32- (aq) -> Mg2+ (aq) + CO32- (aq) + Na+ (aq) + SO42- (aq)
The reaction equation between NaOH and potassium hydrogen tartrate (KHT) is: 2KHT + 2NaOH → 2KNaTartrate + 2H2O
The reaction is the following: H2SO4 + 2NaOH = Na2SO4 + 2H2O
Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================
When sodium hydroxide (NaOH) is reacted with iron (II) sulfate (FeSO4), it forms iron (II) hydroxide (Fe(OH)2) and sodium sulfate (Na2SO4). The balanced chemical equation for the reaction is: 2NaOH + FeSO4 -> Fe(OH)2 + Na2SO4
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MgSO4 + Na2CO3 -> MgCO3 + Na2SO4 Mg2+ (aq) + SO42- (aq) + 2Na+ (aq) + CO32- (aq) -> Mg2+ (aq) + CO32- (aq) + Na+ (aq) + SO42- (aq)
2 NaOH + MgSO4-----Mg(OH)2+Na2SO4 1 MOLE OF MgSO4 produce one mole of Mg(OH)2 SO 1 MWT OF MgSO4 PRODUCE1MWT OF Mg(OH)2 HENCE 120 GM MgSO4 PRODUCE 58 gm OF Mg(OH)2 and so on if x gm of MgSO4 PRODUCE y gm OF Mg(OH)2 x=(120*y)/58 ---- ----
The reaction equation between NaOH and potassium hydrogen tartrate (KHT) is: 2KHT + 2NaOH → 2KNaTartrate + 2H2O
The reaction is the following: H2SO4 + 2NaOH = Na2SO4 + 2H2O
The net ionic equation for NaOH and Na2SO4 when they form a precipitate is simple. It will contain only the atoms that participate in the reaction. Both of these compounds are soluble.
This reaction is:2 NaOH + H2SO4 = Na2SO4 + 2 H2O
When you mix sodium hydroxide (NaOH) and Epsom salt (magnesium sulfate), a double displacement reaction will occur, forming magnesium hydroxide (Mg(OH)2) and sodium sulfate (Na2SO4) as the products. Magnesium hydroxide is a white solid that can precipitate out of the solution.
Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================
The reaction between sulfur trioxide gas (SO3) and sodium hydroxide (NaOH) produces sodium sulfate (Na2SO4) and water (H2O). The balanced equation for this reaction is: SO3 + 2NaOH -> Na2SO4 + H2O
The precipitate is copper(II) hydroxide. The chemical reaction is:2 NaOH + CuSO4 = Cu(OH)2 + Na2SO4
When sodium hydroxide (NaOH) is reacted with iron (II) sulfate (FeSO4), it forms iron (II) hydroxide (Fe(OH)2) and sodium sulfate (Na2SO4). The balanced chemical equation for the reaction is: 2NaOH + FeSO4 -> Fe(OH)2 + Na2SO4