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1 mol N2 = 28g
30C = 303K
At STP, 1mol * 273K is proportional 24L * 760torr. (PV = nRT)
Then we do a little bit of stoichiometry...
10g * 1mol/28g * 24L*760torr/(1mol*273K) * 303K * xL/750torr = 9.6402 L
10.0g of N2 at 30C and 750torr should occupy 9.6402L
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