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Which sequence of coefficient should be placed in the blanks to balance this equation?

I'm not sure which equation you are referring to. Could you please provide more details or specify the equation you are asking about?


What number should be placed in front of CaSO4 to give the same total number of sulfate ions on each side of the equation?

To balance the number of sulfate ions on each side of the equation, a coefficient of 3 should be placed in front of CaSO4. This will give a total of 3 sulfate ions on each side of the equation.


What number should be placed in front of HF to balance this chemical equation?

To balance the chemical equation HF, you would need to place the coefficient "2" in front of HF. This would give you 2HF on both sides, creating a balanced equation: 2HF = 2HF.


If you balance the equation below what should be the coefficient for lithium (Li)?

To determine the coefficient for lithium (Li) in a balanced chemical equation, the complete equation is needed. However, balancing involves ensuring that the number of atoms for each element is the same on both sides of the equation. Once you provide the specific equation, I can help you find the correct coefficient for lithium.


A number placed in front of a chemical formula in a chemical equation is called?

In a chemical Equation ,The reactants are on the left side of a chemical equation and the products are on the right side.The number in front of a chemical formula in a chemical equation is called atoms. They should be a balancing number on both the sides.


When balancing a chemical equation what do you adjust?

You adjust the coefficients in front of each molecule to balance the number of atoms on both sides of the equation. You should not change the subscripts within a molecule when balancing a chemical equation.


Where should coefficients be place when balaning a chemical equation?

Coefficients should be placed in front of the chemical formulas in a chemical equation to balance it. They are used to ensure that the number of atoms of each element is the same on both the reactant and product sides of the equation.


If all of the coefficient and constants in an equation are fractions what should your first step be?

To eradicate the denominators.


If you balance the equation below what should be the coefficient for rubidium (Rb) Rb(s) plus Cl2(g) RbCl(s)?

To balance the equation Rb(s) + Cl2(g) → RbCl(s), you need to ensure that the number of atoms of each element is the same on both sides. Since Cl2 has two chlorine atoms, you need two rubidium chloride (RbCl) units to balance the chlorine. Therefore, the balanced equation is 2 Rb(s) + Cl2(g) → 2 RbCl(s), making the coefficient for rubidium (Rb) 2.


Al plus HCl AlCl3 plus H2 When the above equation is balanced the coefficient of the hydrochloric acid will be?

The balanced equation should be 2Al + 6HCl -> 2AlCl3 + 3H2. Therefore, the coefficient of HCl is 6.


How do you balance SiCl4 plus H20 equals H4SiO4 plus HCl?

To balance the equation SiCl4 + 4H2O → H4SiO4 + 4HCl, you first balance the silicon atoms by putting a coefficient of 1 in front of SiCl4 and H4SiO4. Then balance the chlorine atoms by adding a coefficient of 4 in front of HCl. Next, balance the hydrogen atoms by placing a coefficient of 4 in front of H2O. This gives you a balanced equation: SiCl4 + 4H2O → H4SiO4 + 4HCl.


F you balance the equation below what should be the coefficient for rubidium (Rb) Rb(s) plus Cl2(g) RbCl(s)?

To balance the equation Rb(s) + Cl2(g) → RbCl(s), we need to ensure that the number of atoms for each element is the same on both sides. Since one molecule of Cl2 contains two chlorine atoms, we need two rubidium atoms to react with it. Therefore, the balanced equation is 2 Rb(s) + Cl2(g) → 2 RbCl(s), making the coefficient for rubidium (Rb) equal to 2.