There are 239 nutritional calories (the most common nutitional energy measurement used in USA) in 1,000 kilojoules (the most common energy measurement used in China, where I am currently hanging out.) You can use a .239 conversion factor for any other number of kilojoules or convert it at sites online.
Kj
The energy E in joules (J) is equal to 1 kilojoule times 1000: E (J) = 1kJ × 1000 = 1000J . So 1 kilojoule (kJ) is equal to 1000 joules (J): 1 kJ = 1000 J .
1000 kj, kj means thousand Jules.
8,000 to 10,000 kJ.
To calculate the heat needed to boil 11.2 g of liquid zinc at its boiling point, you would multiply the heat of vaporization by the mass of zinc. Heat = heat of vaporization x mass Heat = 1.76 kJ/g x 11.2 g Heat = 19.7 kJ Therefore, 19.7 kJ of heat is needed to boil 11.2 g of liquid zinc at its boiling point.
350 kJ is 83.6 calories.
3.97 kJ = 0.95 calories.
8700 kJ is 2,077.96 calories.
485 kJ is about 116 calories.
About 1/4 of a calorie per kJ
75?
25 kJ is about six (5.971147416) calories.