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Balanced equation first.

2H2 + O2 -> 2H2O

0.600 moles H2 (1 mole O2/2 moles H2)(6.022 X 10^23/1 mole O2)

= 1.81 X 10^23 molecules of O2 required

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13y ago
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14y ago

Twelve, because each molecule of water has only one oxygen atom, while each mole of oxygen has two atoms of oxygen.

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13y ago

2H2 + O2 -> 2H2O

Therefore, 12.0 moles of water.

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11y ago

only 1 mole of water can be formed. Through stoichiometry you can find that hydrogen is the limiting reactant and it only produces 1 mol of water, or aprox. 18 grams of H2O.

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12y ago

5.40 mol H2O

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12y ago

3 moles of oxygen.

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11y ago

13 mole

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Q: How many moles of water can be produced from 6.0 mol of oxygen?
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