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What mass of hcl is consumed by the reaction of 2.50 moles of magnesium in equation mg plus hcl equals mgcl2 plus h2?
The balanced chemical equation is: Mg + 2HCl → MgCl2 + H2. Since magnesium reacts with 2 moles of HCl to produce 1 mole of hydrogen, the molar ratio is 2:1. Therefore, with 2.50 moles of magnesium, 5.00 moles of HCl will be consumed. To find the mass of HCl consumed, use the molar mass of HCl (molar mass of HCl = 36.46 g/mol) and the number of moles consumed in the reaction. Thus, the mass of HCl consumed will be 182.3 g.
How many grams of HCl can be prepared from 2.00 mol H2So4 and 150 g NaCl?
2NaCl + H2SO4 ----> 2HCl + Na2SO4 *molar mass of H2SO4 is 98.09g *molar mass of NaCl is 58.44g *molar mass HCl is is 36.46g Moles NaCl = 150 g / 58.44 = 2.56 The ratio between NaCl and H2SO4 is 2 : 1 so NaCl is the limiting reactant We would get 2.56 mol HCl => 2.56 mol x 36.46 g/mol = 93.3 g
.25 g of zinc reacted with 10 mL of HCl what is the moles of zinc reacted?
*first you set the equation: -(10mL of HCl)(1 mol of HCl)/(22.4 mL of HCl)= .446 mol of HCl *you divide by the volume of HCl which is 22.4 at STP. *Then you will divide that .446 mol of HCl with the mol of Zn, which is 1: -(.446 mol of HCl)( I mol of Zn)/(1 mol of HCl)= .446 mol Zn
How many moles are present in 21.2 g hydrogen chloride?
hydrogen chloride = H+1, Cl-1 = HCl H = 1.008 Cl = 35.453 HCl = 36.458 g/mol 21.1 g x 1 mol HCl/36.458g = .579 mol HCl The ions of hydrogen chloride balance out so the formula is HCl. You add the atomic weights of the individual elements to get a grams/mole for the molecule HCl. You take the information that was given, 21.1g of HCl, and multiply it by the fact that 1 mole of HCl is 36.458g. Grams cross out and you're left with 21.1 x 1 mol / 36.458 = .579 mol. This is how many moles are in 21.1g of HCl.
How do calculate molarity example being calculate molarity of 6.5g of hcl solution per liter solution?
All you have to do is convert the 6.5 g HCl solution into moles, and then plug that value into the molarity formula. If you need help, here are the formulas: # mol = (mass of substance)/(molar mass) - the molar mass is just the molecular mass of the substance expressed in grams :) Molarity (M) = (# mol solute)/(# L solution) - the solute, in this case, is the HCl, and the solution is just one, based on your question Happy Calculating!!!
How many moles are in 2 grams of HCL?
To find the number of moles in 2 grams of HCl, you need to divide the mass by the molar mass of HCl. The molar mass of HCl is approximately 36.46 g/mol. Therefore, 2 grams of HCl is equal to 2/36.46 = 0.055 moles.
How many moles of HCL are there in 108 grams of the substance?
To find the number of moles in 108 grams of HCl, you need to know the molar mass of HCl, which is about 36.5 g/mol. You can then use this molar mass to calculate the number of moles by dividing the given mass by the molar mass. In this case, 108 grams divided by 36.5 g/mol gives you about 2.96 moles of HCl.
How many moles are present in a sample of HCl with a mass of 3.65?
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How many moles are in 23.34 grams of h c l?
To find the number of moles in 23.34 grams of HCl, you need to divide the mass by the molar mass of HCl. Calculate the molar mass of HCl (hydrochloric acid), which is 1 (hydrogen) + 35.5 (chlorine) = 36.5 g/mol. Divide the mass of 23.34 grams by the molar mass of 36.5 g/mol to find the number of moles.
What mass of hcl is consumed by the reaction of 2.50 moles of magnesium in equation mg plus hcl equals mgcl2 plus h2?
The balanced chemical equation is: Mg + 2HCl → MgCl2 + H2. Since magnesium reacts with 2 moles of HCl to produce 1 mole of hydrogen, the molar ratio is 2:1. Therefore, with 2.50 moles of magnesium, 5.00 moles of HCl will be consumed. To find the mass of HCl consumed, use the molar mass of HCl (molar mass of HCl = 36.46 g/mol) and the number of moles consumed in the reaction. Thus, the mass of HCl consumed will be 182.3 g.
How many moles of atoms are present in 154 g of HCl?
Divide by molar mass and check the units(italicalized):0.140 (g HCl) / 36.45 (g.mol-1HCl) = 3.84*10-3 mol HCl
How many moles HCl in 8.3 g HCl?
8.3 grams HCl (1 mole HCl/36.458 grams) = 0.23 moles HCl ------------------------
How many grams of HCl can be prepared from 2.00 mol H2So4 and 150 g NaCl?
2NaCl + H2SO4 ----> 2HCl + Na2SO4 *molar mass of H2SO4 is 98.09g *molar mass of NaCl is 58.44g *molar mass HCl is is 36.46g Moles NaCl = 150 g / 58.44 = 2.56 The ratio between NaCl and H2SO4 is 2 : 1 so NaCl is the limiting reactant We would get 2.56 mol HCl => 2.56 mol x 36.46 g/mol = 93.3 g
Magnesium reacts with hydrochloric acid HCl to form magnesium chloride and hydrogen gas. The reaction is Mg plus 2HCl and rarr MgCl2 plus H2 What is the mass of HCl that would be required to completel?
The reaction is balanced, so the mole ratio of Mg to HCl is 1:2. Calculate the molar mass of HCl (1 mol HCl = 1g + 1g = 36.5g), then use stoichiometry to convert the mass of Mg to moles of HCl. Finally, divide the mass of Mg by 1 (from the ratio 1:2) and multiply by the molar mass of HCl to find the mass needed.
What is the mass of HCl that would be required to completely react with 5.2 grams of Mg?
The balanced chemical equation for the reaction between HCl and Mg is: Mg + 2HCl -> MgCl2 + H2. One mole of Mg reacts with 2 moles of HCl. Calculate the moles of Mg in 5.2 grams using the molar mass of Mg. Then use the mole ratio to find the moles of HCl needed, and finally calculate the mass of HCl using its molar mass.
How many grams of HCl are contained in 4.25mL of a 0.405M aqueous solution of HCl?
M * V = n 0.405 M * 0.00425 ml = 0.00172125 mole of HCl The molar mass of HCl is: 1.007947 + 35.453 = 36.460947 g/mole m = mm * n So the mass in gram is: 36.460947 g/mole * 0.00172125 mole = 0.0628 gram
One reaction that produces hydrogen gas can be represented by the unbalanced chemical equation Mg(s) plus HCl(aq) and minus and rarr MgCl2(aq) plus H2(g) . What mass of HCl is consumed by the reac- ti?
The balanced equation for the reaction is: Mg(s) + 2HCl(aq) -> MgCl2(aq) + H2(g). To calculate the mass of HCl consumed, you need to know the molar mass of HCl (approximately 36.46 g/mol) and the molar ratio between HCl and Mg in the balanced equation (2 moles of HCl per 1 mole of Mg). Once you have the moles of Mg given, you can use the mole ratio to calculate the moles of HCl consumed, and then convert that to mass using the molar mass of HCl.
