What is the empirical formula for C5H15O5?

Answer 1

The requirements for an empirical formula are that it give the correct ratios between all pairs of atoms in the actual molecule and have subscripts (including the value 1 implied by lack of an explicit subscript) with the lowest possible values to achieve all the correct ratios. To meet the latter condition, either one subscript must be one or the two smallest subscripts must be distinct Prime number. The formula of the compound given has only one prime number subscript, 5. If all subscripts in the molecular formula are divided by the same number to yield an integral quotient, the resulting formula will still be empirically correct. In the given molecular formula, all the subscripts are integrally divisible by 5. Therefore, the empirical formula is CH3O2.

Answer 2

Carbon has a molar mass of 12.011 g/mol, hydrogen has a molar mass of 1.008 g/mol and nitrogen has a molar mass of 14.007 g/mol. This means that the compound is 4.454 parts carbon to 15.37 parts hydrogen to 2.220 parts nitrogen. By reduction, the empirical formula becomes C2H7N.

Answer 3

The empirical formula for the compound C10H25O5 is CH5O. The empirical formula is the simplest whole number ratio of elements in the compound.

Answer 4

C2 h7 n; c2h7n

Answer 5

Formula: C3H8N

Answer 6

C2H5O by franklin santos

Answer 7

C2h7n

Answer 8

nh3

Answer 9

66