You have stated the concentration as 0.9; however this does not include units, which are usually measured in moles per litre (molL-1) or grams per litre/tonnes per cubic metre (gL-1/Tm-3). Edit (AY12345): mol/L is called molarity(M). Another common unit is molality (m) which is moles of solute over kg of solvent
CaCL2 on its own cannot have a concentration. It would have to be dissolved in a solution first. Then, from the amount of CaCl2 which is dissolved in a certain amount of a solute (such as water), you would be able to figure out the concentration.
You would have a saturated solution because at that temperature and concentration, the amount of sodium chloride being dissolved is in equilibrium with the amount that can be dissolved. Any more added would exceed its solubility.
To make a 1M solution of sodium chloride in 1 liter of water, you would need 58.44 grams of sodium chloride. This is based on the molecular weight of sodium chloride, which is 58.44 g/mol.
Yes, a sodium chloride solution at a concentration of 1.8% would be hypertonic, meaning it has a higher solute concentration compared to the surrounding cells or environment. This can cause water to move out of the cells through osmosis, leading to dehydration and potential cell shrinkage.
The molecular weight of NaCl is 58.44; sodium =22.99; Chlorine=35.45. A 1 molar solution is the molecular weight in grams in 1 litre of water, so a 3.5 molar solution would be 58.44g multiplied by 3.5, which is 204.54g in 1L.
A hypertonic solution of sodium chloride would have a higher concentration of salt compared to normal body cells. This typically occurs at concentrations greater than 0.9% sodium chloride.
Evaporate the water.
NaCl is neutral so it will produce a solution with a pH of 7 in any concentration.
The concentration of sodium chloride would be 1.5 moles per liter (M). If 200 ml is used, that would be 0.3 moles of sodium chloride.
Saline solution should always be in given as a concentration of 0.9% sodium chloride (NaCl).
it would be the solute
Water solution of sodium chloride is neutral.
A water solution of sodium chloride is neutral.
No, they would not form a solution.
No, adding solid sodium hydroxide to neutralize hydrochloric acid (HCl) would not cause sodium chloride to redissolve. The reaction between sodium hydroxide and hydrochloric acid forms water and sodium chloride, which remains in its dissolved form. The addition of solid sodium hydroxide would simply further neutralize the acid and increase the concentration of the resulting sodium chloride solution.
A water solution of sodium chloride is neutral.
CaCL2 on its own cannot have a concentration. It would have to be dissolved in a solution first. Then, from the amount of CaCl2 which is dissolved in a certain amount of a solute (such as water), you would be able to figure out the concentration.