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What mass of sulfur dioxide would be produced if 64 tons of sulfur was completely reacted with oxygen gas?
If sulfur is completely reacted with oxygen gas to form sulfur dioxide, the molar ratio between sulfur and sulfur dioxide is 1:1. This means that 64 tons of sulfur would produce 64 tons of sulfur dioxide.
What percent of sulfur in sulfur dioxide?
Sulfur dioxide (SO2) consists of one sulfur atom and two oxygen atoms. The percentage of sulfur in sulfur dioxide is calculated as the mass of sulfur divided by the total mass of the compound, which is 32.07 grams per mole for sulfur and 64.07 grams per mole for sulfur dioxide. This means that sulfur represents 50% of the total mass of sulfur dioxide.
What is the percent mass of sulfur in sulfur dioxide?
69
What is the percent by mass in sulfur in sulfur oxide?
The percent by mass of sulfur in a sulfur oxide compound can vary depending on the specific compound. For example, in sulfur dioxide (SO2), which contains one sulfur atom and two oxygen atoms, the percent by mass of sulfur would be approximately 50%. In sulfur trioxide (SO3), which contains one sulfur atom and three oxygen atoms, the percent by mass of sulfur would be approximately 40%.
A mass of ammonia weighs 2.00g.What mass of sulphur dioxide contains the same number of molecules as are in 2.00g ammonia?
To find the mass of sulfur dioxide (SO₂) that contains the same number of molecules as 2 grams of ammonia (NH₃), you can use the concept of moles and the molar mass. **Find the number of moles of ammonia:** [ \text{Moles of NH₃} = \frac{\text{Mass of NH₃}}{\text{Molar mass of NH₃}} ] The molar mass of ammonia (NH₃) is approximately 17 grams/mol. **Use Avogadro's Number:** According to Avogadro's number, 1 mole of any substance contains the same number of entities (atoms, molecules, etc.), which is approximately (6.022 \times 10^{23}). **Find the number of molecules of ammonia:** [ \text{Number of NH₃ molecules} = \text{Moles of NH₃} \times (6.022 \times 10^{23}) ] **Convert to moles of sulfur dioxide:** Since the number of molecules is the same for both substances, the moles of sulfur dioxide (SO₂) would be the same as the moles of ammonia. [ \text{Moles of SO₂} = \text{Moles of NH₃} ] **Find the mass of sulfur dioxide:** [ \text{Mass of SO₂} = \text{Moles of SO₂} \times \text{Molar mass of SO₂} ] The molar mass of sulfur dioxide (SO₂) is approximately 64 grams/mol. Now, you can substitute the values into the equations to find the mass of sulfur dioxide.
What mass of sulfur dioxide would be produced if 64 tons of sulfur was completely reacted with oxygen gas?
If sulfur is completely reacted with oxygen gas to form sulfur dioxide, the molar ratio between sulfur and sulfur dioxide is 1:1. This means that 64 tons of sulfur would produce 64 tons of sulfur dioxide.
What percent of sulfur in sulfur dioxide?
Sulfur dioxide (SO2) consists of one sulfur atom and two oxygen atoms. The percentage of sulfur in sulfur dioxide is calculated as the mass of sulfur divided by the total mass of the compound, which is 32.07 grams per mole for sulfur and 64.07 grams per mole for sulfur dioxide. This means that sulfur represents 50% of the total mass of sulfur dioxide.
What is the percent by mass of sulfur in sulfur dioxide?
The molar mass of sulfur dioxide (SO2) is 64.06 g/mol. The molar mass of sulfur is 32.06 g/mol. Calculate the mass percent of sulfur in SO2 using the formula (mass of sulfur / mass of SO2) x 100%. This gives a mass percent of sulfur in SO2 as 50%.
What is the percent mass of sulfur in sulfur dioxide?
69
What is the molar mass of so2?
The molecular mass of sulfur dioxide is 64,07.
What is the percent sulfur in sulfur dioxide?
Sulfur dioxide (SO2) is composed of one sulfur atom and two oxygen atoms. To calculate the percent sulfur, divide the atomic mass of sulfur by the molecular mass of sulfur dioxide, then multiply by 100. The percent sulfur in sulfur dioxide is approximately 50%.
How much sulfur dioxide can be produced from 64kg of sulfur?
The molar mass of sulfur is 32 g/mol and the molar mass of sulfur dioxide is 64 g/mol. Thus, from 64 kg of sulfur, you can produce 1280 kg (1.28 metric tons) of sulfur dioxide using stoichiometry.
How many atoms are in 37.14 grams of sulfur dioxide?
Sulfur has relative atomic mass of 32 and oxygen have that of 16. The molar mass of sulfur dioxide is 64 grams per mole. Therefore there is approximately 0.58 moles (37.14/64) of sulfur dioxide in given weight.
What is the mass prcent of oxygen in sulfur dioxide?
A sulfur dioxide has one sulfur atom and two oxygen atoms. Therefore, considering a mole of sulfur dioxide (64g); there is 32g of sulfur and 32g of oxygen. Hence the mass percent of oxygen is 50%.
How do the rates of diffusion of oxygen and sulfur dioxide compare Molar masses Oxygen is 32 gmol and sulfur dioxide is 64 gmol?
The rate of diffusion is inversely proportional to the square root of the molar mass of the gas. Since sulfur dioxide has a molar mass twice that of oxygen, it will diffuse at a slower rate compared to oxygen.
What is the percent by mass in sulfur in sulfur oxide?
The percent by mass of sulfur in a sulfur oxide compound can vary depending on the specific compound. For example, in sulfur dioxide (SO2), which contains one sulfur atom and two oxygen atoms, the percent by mass of sulfur would be approximately 50%. In sulfur trioxide (SO3), which contains one sulfur atom and three oxygen atoms, the percent by mass of sulfur would be approximately 40%.
What mass of sulfur must be used to produce 12.6L of sulfur dioxide (SO2) at STP?
Assuming the equation for the reaction is S + O2 --> SO2, you first determine how many moles are in 12.6L of SO2: 12.6/22.4 = 0.56mol (22.4L = 1mol of any gas at STP.) The equation's molar ratio tells us that 0.56mol SO2 means 0.56mol S, because everything's in a 1:1 ratio. Now, consider sulfur's atomic mass of 32.1g/mol. 32.1x0.56 = approx. 18g sulfur. Now, if your sulfur is the S8 allotrope, you'll have to re-calculate for that.
