88.6
To determine the theoretical yield of aluminum oxide, we first need to write and balance the chemical equation: 4 Al + 3 O2 -> 2 Al2O3. From the equation, we can see that 4 moles of Al reacts with 3 moles of O2 to produce 2 moles of Al2O3. Calculate the moles of Al and O2 provided, convert each to moles of Al2O3, and find the limiting reactant to determine the theoretical yield.
All active metals below Hydrogen in the galvanic series.
Yes. In fact, aluminum oxidizes faster than almost any other metal, which is why aluminum foil will, actually, remove rust: The abrasion removes the coating of aluminum oxide that covers all metallic aluminum exposed to the air, and the exposed aluminum metal wants to be oxidized so badly that it will actually steal oxygen from iron oxide, AKA rust, and reduce it back to iron metal. Which is why aluminum foil will, in fact, remove rust. This reaction, interestingly, is the same one that makes thermite work.
Aluminum oxide. The oxide forms almost instantaneously in the presence of air or water or any environment that contains oxygen.
The most common chemical elements in the crust are oxygen (46.6%), silicon (27.7), aluminum (8.1), iron (5.0), calcium (3.6), potassium (2.8), sodium (2.6), and magnesium (2.1).Oxygen is a non-metal and silicon is a metalloid - so the most common metal is aluminum.
The balanced chemical equation for the reaction is 4Al + 3O2 -> 2Al2O3. Since the molar ratio between aluminum and oxygen is 4:3, aluminum is the limiting reagent. Therefore, the theoretical yield of aluminum oxide is based on the 3.00 mol of aluminum. Using stoichiometry, the theoretical yield of aluminum oxide would be 3.00 mol of Al * (2 mol Al2O3 / 4 mol Al) = 1.50 mol of Al2O3.
The balanced chemical equation for the reaction between aluminum and oxygen to form aluminum oxide is: 4Al + 3O2 → 2Al2O3. From the balanced equation, we can see that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. Therefore, if 3.40 mol of aluminum and 2.85 mol of oxygen are reacted, the limiting reactant is oxygen. Thus, 3.40 mol of aluminum would theoretically produce 1.90 mol of aluminum oxide.
The balanced chemical equation for the formation of aluminum oxide is: 4Al + 3O2 -> 2Al2O3. This means that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. Using the given moles of aluminum and oxygen, we can determine the limiting reactant and the theoretical yield of aluminum oxide. In this case, the oxygen is the limiting reactant, which means it will run out first. Therefore, all of the 2.70 mol of oxygen will react with aluminum to produce aluminum oxide. Since the ratio of aluminum to aluminum oxide is 4:2, the 2.70 mol of oxygen will react with (2/3)*2.70 mol of aluminum to produce aluminum oxide, which is approximately 1.80 mol.
The balanced equation for the reaction is 4Al + 3O2 -> 2Al2O3. From the stoichiometry of the reaction, 3.40 mol of Al will react with 2.55 mol of O2 to produce 4.25 mol of Al2O3. Hence, the theoretical yield of aluminum oxide is 4.25 mol.
The balanced chemical equation for the reaction is 4Al + 3O2 → 2Al2O3. Since the stoichiometry ratio is 4:3, the limiting reactant is aluminum since it provides less moles of product. Therefore, 2.00 mol of aluminum will produce 2.00 mol of aluminum oxide.
To determine the theoretical yield of aluminum oxide, we first need to write a balanced chemical equation for the reaction between aluminum and oxygen to form aluminum oxide. The balanced equation is 4Al + 3O2 -> 2Al2O3. From the equation, we can see that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. Therefore, if 2.40 moles of aluminum is exposed to 2.10 moles of oxygen, the limiting reactant is oxygen. Using stoichiometry, we can calculate the theoretical yield of aluminum oxide, which is 1.60 moles.
oxygen is a non metal
To determine the theoretical yield of aluminum oxide (Al₂O₃), we start with the balanced chemical reaction: 4 Al + 3 O₂ → 2 Al₂O₃. From the stoichiometry, 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. Given 1.60 moles of aluminum, we can find the limiting reactant. Since 1.60 moles of Al would require 1.20 moles of O₂ (which is less than the available 1.50 moles), aluminum is the limiting reactant. Thus, 1.60 moles of Al can produce 0.80 moles of Al₂O₃ (from 2 moles Al producing 1 mole Al₂O₃), so the theoretical yield of aluminum oxide is 0.80 moles.
Iron is the transition metal that rusts when exposed to oxygen, forming iron oxide.
Iron is a self-protecting metal that forms a protective layer of iron oxide (rust) when exposed to oxygen and moisture, which helps prevent further corrosion.
The symbol for metal oxides is typically a combination of the chemical symbol for the metal and the chemical symbol for oxygen. For example, the metal oxide formed by aluminum and oxygen is represented as Al2O3, where "Al" is the symbol for aluminum and "O" is the symbol for oxygen.
To determine the theoretical yield of aluminum oxide, we first need to write and balance the chemical equation: 4 Al + 3 O2 -> 2 Al2O3. From the equation, we can see that 4 moles of Al reacts with 3 moles of O2 to produce 2 moles of Al2O3. Calculate the moles of Al and O2 provided, convert each to moles of Al2O3, and find the limiting reactant to determine the theoretical yield.