iron
No. Metals have a relatively low specific heat.
One method is to measure the temperature change when a known amount of the metal reacts with water in a calorimeter. By knowing the heat released or absorbed during the reaction and the mass of the metal, the specific heat can be calculated using the equation q = mcΔT, where q is the heat, m is the mass, c is the specific heat, and ΔT is the temperature change.
A thermometer can be used to test the purity of a metal by measuring its specific heat capacity. Different metals have different specific heat capacities, so comparing the measured value to the known values for pure gold or iron can indicate the level of impurities present in the sample. A lower specific heat capacity than the known value may indicate impurities in the metal.
The specific heat of water is 4184 J kg-1 K-1 The specific heat of copper 385 J kg-1 K-1. So the answer is no.
== == This answer is taken straight off yahoo answers and I thought it would be helpful to "spread the wealth." here it is. change in temperature of metal, 75 - 18.3 = 56.7 'C change in temperature of water, 18.3 - 15 = 3.3 'C energy gained by water, assuming Cp water = 4.1813 J/g/'C using the formula, Q = mCp(theta) where, Q = energy in Joules m = mass in grams Cp = specific heat capacity in J/g/'C theta = change in temperature in 'C 3.3 * 150 * 4.1813 = 2.06974 kJ energy gained by water = energy dissipated by metal using the formula, Q = mCp(theta) and solving for Cp Cp of metal = 2.06974 k / 56.7 *150 = 0.2434 J/g/'C
No. Metals have a relatively low specific heat.
No, water splashing out of the calorimeter will not affect the specific heat of the metal. The specific heat of a substance is an intrinsic property that remains constant regardless of the environment.
A measured amount of water is used in determining the specific heat of a metal object because water has a well-defined specific heat capacity (1 calorie/gram °C) and is readily available. By measuring the temperature change of a known mass of water when a metal object is immersed in it, and knowing the specific heat of water, we can calculate the specific heat of the metal object.
It depends on what the metal is. Different materials have different specific heats and will take various amount of energy to heat up. You need to find the specific heat of the metal used. Use Q=CmT Q=amount of energy C=specific heat m=mass T=change in temp
The answer lies in a property called "specific heat". Specific heat describes the amount of energy needed to raise a material's temperature by one degree. Metal has a low specific heat, so it warms up fast and cools fast. Wood has a higher specific heat, so these processes are slower. In both cases, heat (energy) is transferred from your hand to the wood/metal, but since this happens faster with metal, it feels colder.
at least 1 kelvin
To determine which block will increase its temperature the most, compare the specific heat capacity of each metal. The metal with the lowest specific heat capacity will increase its temperature the most with the same amount of heat energy absorbed. Choose the metal with the lowest specific heat capacity among the four blocks.
Gold has the lowest specific heat capacity.
I would like to start off by saying that: Energy absorbed by metal = mass of metal x specific heat capacity of metal x change in temperature of the metal If the same amount of energy is given to all three metals, there would be the highest temperature increase in the metal with the lowest specific heat capacity. Therefore, Silver would be the answer.
Without stating units, it is impossible to answer this question accurately. However, the equation you would need is q=mc∆T, where q is the heat flow (the 53.0 listed, likely Joules), m is the mass of the unknown metal (11.1, likely grams), c is the specific heat of the metal (the unknown you need to solve for), and ∆T is the change in temperature of the metal (24.1-13.0, likely Celcius). Rearranged to solve for specific heat, the question is c=q/m∆T.
An example of a substance with low specific heat is metal, such as iron or aluminum. These materials heat up quickly when exposed to heat and cool down quickly as well, due to their low specific heat capacity.
The specific heat capacity of the metal object can be calculated using the formula q = mcΔT, where q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the temperature change. The heat gained by the metal is equal to the heat lost by the water in the calorimeter, so q_metal = -q_water. By setting up the equation and solving for c, you can find the specific heat capacity of the metal.