the address of variable (pointer) that contains array
Any of these: arr, &arr, &arr[0]
Wright a 'C' program for storage representation of 2-D array.
When an array name is passed as a function argument, the address of the first element is passed to the function. In a way, this is implicit call by reference. The receiving function can treat that address as a pointer, or as an array name, and it can manipulate the actual calling argument if desired.
Reference:cprogramming-bd.com/c_page1.aspx# array programming
Mentioning the array name in C or C++ gives the base address in all contexts except one. Syntactically, the compiler treats the array name as a pointer to the first element. You can reference elements using array syntax, a[n], or using pointer syntax, *(a+n), and you can even mix the usages within an expression. When you pass an array name as a function argument, you are passing the "value of the pointer", which means that you are implicitly passing the array by reference, even though all parameters in functions are "call by value". There is, however, one very important distinction. While an array name is referentially the same as a pointer, it is not a pointer in that it does not occupy program referential space in the process. This means that, while you can change the value of a pointer, and thus the address to which it points, you can not change the value of an array name. This distinction is what we call R-Value (array or pointer) as opposed to L-Value (pointer only), i.e. can the object appear on the left sign of an assignment operator.
The name of the array means the address of the first element, so 'arr==&arr[0]'
Wright a 'C' program for storage representation of 2-D array.
cod a program student degree array in c language
When an array name is passed as a function argument, the address of the first element is passed to the function. In a way, this is implicit call by reference. The receiving function can treat that address as a pointer, or as an array name, and it can manipulate the actual calling argument if desired.
== Java does not allow reference to memory locations. == In C: for (i=0; i<n; ++i) printf ("a[%d] is at %p\n", i, &a[i]);
cod a program student degree array in c language
Reference:cprogramming-bd.com/c_page1.aspx# array programming
Mentioning the array name in C or C++ gives the base address in all contexts except one. Syntactically, the compiler treats the array name as a pointer to the first element. You can reference elements using array syntax, a[n], or using pointer syntax, *(a+n), and you can even mix the usages within an expression. When you pass an array name as a function argument, you are passing the "value of the pointer", which means that you are implicitly passing the array by reference, even though all parameters in functions are "call by value". There is, however, one very important distinction. While an array name is referentially the same as a pointer, it is not a pointer in that it does not occupy program referential space in the process. This means that, while you can change the value of a pointer, and thus the address to which it points, you can not change the value of an array name. This distinction is what we call R-Value (array or pointer) as opposed to L-Value (pointer only), i.e. can the object appear on the left sign of an assignment operator.
An array always stores the values in its different shells. Whenever the shell position or number or address is mentioned it means the address of the required value is mentioned. then the value of the mentioned address is fetched. So, array is a reference type in c language.
The name of the array means the address of the first element, so 'arr==&arr[0]'
the example of array over charcter variables is char ["string"]
yes
array type