How do you swap two numbers without using third variable in c plus plus?

Answer 1

int a,b,temp;

printf("enter the values of a & b"); //could be done in diff. two lines for the input//

scanf("%d %d",&a,&b);

printf("the values of a=%d & b=%d before swapping",a,b);

// swapping without using arithmetic operators.....

temp=a;

a=b;

b=temp;

printf("the values of a=%d & b=%d after swapping",a,b);

getch();

Answer 2

int iA = 5;

int iB = 6;

int iA = iA + iB; // iA is now 11

int iB = iA - iB; // iB is now 5

int iA = iA - iB; // iA is now 6

Note: Even though no overt variable has been created, the compiler has created temporary variables because a variable left of the equal sign has been used on the right.

Answer 3

# include

# include

void main()

{

clrscr();

int a,b;

printf ("Enter the first value:");

scanf ("%d",& a );

printf ("Enter the second value:");

scanf ("%d",& b );

printf ("\n\nBefor swaping the values ");

printf ("\nThe first value is %d",a);

printf ("\nthe second value is %d",b);

printf ("\n\nAfter swaping the values ");

printf ("\nThe first value is %d",b);

printf ("\nthe second value is %d",a);

}

OUTPUT

Enter the first value:8

Enter the second value:5

Befor swaping the values

The first value is 8

the second value 5

After swaping the values

The first value is 5

the second value 8

Answer 4

Swapping two values without using a third variable is made possible through a series of three XOR/assign operations, alternating the operands.

Consider the following declarations:

int x = 0;

int y = 1;

The following statement will swap the values of x and y:

x ^= y ^= x ^= y; // swap

The same statement implemented as a function:

void swap(int &x, int &y){ x ^= y ^= x ^= y; }

Answer 5

void swap (int* a, int* b) {

int temp = *a;

*a = *b;

*b = t;

}

Answer 6

With a temporary variabele:

tmp= x, x=y, y=tmp;

Answer 7

void swap (int* x, int* y) { (*x)^=(*y)^=(*x)^=(*y);

}

Answer 8

swap (int *a, int *b) {

*a ^= *b;

*b ^= *a;

*a ^= *b;

}