How operator overloading differ from function overloading?

Answer 1

Function overloading is multiple definition with different signatures(the parameters should be different) for the same function. The parameter list have to be different in each definition. The compiler will not accept if the return type alone is changed.

Operator overloading is defining a function for a particular operator. The operator loading function can not be overloaded through function overloading.

Answer 2

Operator overloading means defining what the operators ie + - * / & | etc mean in terms of your object, by writing appropriate methods in the object's code. This is not permitted in java.

Method overloading is using the same method name in methods with different paramters ie

setSize(Dimension d)

setSize(int height, int width)

Answer 3

Function overloading refers to using the same function name in the same scope with multiple versions depending on the parameters provided. Operator overloading is a specialized version of function overloading, and refers specifically to using operators instead of function names. These are usually designated with the keyword "operator".

Function overloading:

void doSomething(int arg1);

void doSomething(int arg1, int arg2);

Operator overloading:

obj& operator +(obj arg1, obj arg2);

Answer 4

There is no difference. Operator overloads should always be implemented with an equivalent function overload. That is, an operator overload should always call the appropriate function overload, thus giving the user the option of using the operator or the function.

Indeed, aside from the relational operators (<, <=, ==, >, >= and !=) and assignment operator (=), operator overloads are not actually required unless they would allow consumers to use the object in a more intuitive way. If there is any ambiguity regarding the purpose of an operator, do not provide an operator at all -- use a function equivalent instead.