What is the c program to find the octal equivalent of an integer?

Answer 1

void Decimal_to_Octal()
{
int n,r[10],i;
cout<<"Enter a number to find it's octal equivalent";
cin>>n;
cout<<"The octal equivalent of "<for(i=0;n!=0;i++)
{
r[i]=n%8;
n=n/8;
}
i--;
for(;i>=0;i--)
cout<count<}

Answer 2

In programming code you can write numbers in binary, decimal, octal, hex and maybe even other base number systems if supported.

Before jumping into a program that actually can convert your inputted number from decimal to octal, we should look how it is done manually.

Decimal number: 345

Divide 345 by 8:

345 / 8 = [43] reminder = 1; 1 becomes LSD(Least Significant Digit), the digit which will be at the end of the number;

Now we need to divide 43 by 8:

43 / 8 = [5] reminder = 3;

Now we need to divide 5 by 8;

5 / 8 = [0] reminder = 5; 5 becomes MSD(Most Significant Digit), the digit which will be at the beginning of the number;

Now 345 in decimal is equal 531 in octal.

Here is a program that works using this method:

#include

#include

int arrToInt(int nums[], int cnt);

int main()

{

int num;

int cnt = 0;

int nums[100];

printf("Enter the number in decimal: ");

scanf("%d", &num);

while (num != 0)

{

/* we save all reminders in the array */

nums[cnt++] = num % 8;

num = num / 8;

}

printf("Number in octal: %d\n", arrToInt(nums, cnt));

return 0;

getch();

}

int arrToInt(int nums[], int cnt)

{

int tmp = 0;

for (cnt = cnt - 1; cnt >= 0; cnt--)

{

tmp += nums[cnt] * pow(10, cnt);

}

return tmp;

}

Testing:

Enter the number in decimal: 0

Number in octal: 0

Enter the number in decimal: 7

Number in octal: 7

Enter the number in decimal: 8

Number in octal: 10

Enter the number in decimal: 345

Number in octal: 531

Enter the number in decimal: 264

Number in octal: 410

Answer 3

/*

Program to convert the given number into binary,octal and deciaml

*/

import java.io.*;

class Main

{

public static void main(String agrs[])

{

int a=90;

System.out.println("\nGiven number is "+a);

System.out.println("\nThe Binary equivalent of ""+a+"" is "+Integer.toString(a,2));

System.out.println("The Hexadecimal equivalent of ""+a+" is "+Integer.toString(a,16));

System.out.println("The Octal equivalent of ""+a+"" is "+Integer.toString(a,8));

}

}

Answer 4

#include<stdio.h>

#include<conio.h>

void main()

{

unsigned int n;

clrscr();

printf("\n\tEnter the number : ");

scanf("%u",&n);

printf("\n\tThe input integer (in decimal) = %u\n",n);

printf("\n\tThe input integer (in octadecimal) = %o\n",n);

getch();

}

Answer 5

int iInteger ={ ... some value ... };

printf("%o\n", iInteger);

Answer 6

printf ("%d is %o in octal\n", x, x);

Answer 7

The last number in the world is air