C plus plus program to generate Fibonacci series?

Answer 1

#include<stdio.h>

#include<conio.h>

main()

{

int a=0,b=1,c,i,n;

clrscr();

printf("enter the limit of series\n");

scanf("%d",&n);

if(n==0)

printf("%d\n",a);

else

printf("%d\n%d\n",a,b);

for(i=2;i<=n;i++)

{

c=a+b;

printf("%d\n",c);

a=b;

b=c;

}

getch();

}

Answer 2

#include

void main()

{

int i,f1=0,f2=1,f,n,sum=0;

printf("enter the range dou you want");

scanf("%d",&n); //it identifieses the range number do you want

printf("d",f1,f2);// first two fibanacci numbers

for(i=1;f<=n;i++) //to generate Fibonacci numbers

{

f1=f2;

f2=f;

f=f1+f2;

s=s+f;

printf("%d",f);

} //end for loop

printf("%d",sum);

}end of main

Answer 3

#include<iostream>

using namespace std; int main()

{

cout << "Fibonacci sequence up to 100...

int f1 = 0;

int f2 = 1;

cout << f1 << endl;

while (f2<100)

{

cout << f2 << endl;

int next = f1 + f2;

f1 = f2;

f2 = next;

}

}

Answer 4

#include<iostream>

int main()

{

int x=0, y=1, sum=x+y;

std::cout<<x<<" ";

std::cout<<y<<" ";

while( y<1000000 )

{

std::cout<<(y+=x)<<" ";

x=y-x;

sum+=y;

}

std::cout<<std::endl;

std::cout<<"Sum = "<<sum<<std::endl;

return(0);

}

Answer 5

#include<iostream>

int main()

{

int x=0, y=1;

std::cout<<x<<" ";

std::cout<<y<<" ";

for( ;y<1000000; )

{

std::cout<<(y+=x)<<" ";

x=y-x;

}

std::cout<<std::endl;

return(0);

}

Answer 6

#include<iostream>

int main()

{

int x=0, y=1;

std::cout<<x<<" ";

std::cout<<y<<" ";

for( ;y<1000000; )

{

std::cout<<(y+=x)<<" ";

x=y-x;

}

std::cout<<std::endl;

return(0);

}

Answer 7

This question has been asked many times and answered many times please refer to previous answers. Also any future questions you may have have probably been asked and answered by previous students doing the same course as you.

Actually doing the work your self rather than looking for the easy way will benefit you the most because you will learn something. Using someone else work is deceitful and will only cause you to be a failure as a person and in your academic endeavors.

Answer 8

#include<iostream>

int main()

{

int x=0, y=1;

std::cout<<x<<" ";

std::cout<<y<<" ";

while( y<1000000 )

{

std::cout<<(y+=x)<<" ";

x=y-x;

}

std::cout<<std::endl;

return(0);

}