How do you write a C program to print the diagonal element of a NxN matrix?

Answer 1

#include<stdio.h>

#include<conio.h>

void main()

{

int a[3][3],b[3][3],c[3][3],r,c;

for(r=0;r<=3;r++)

{

for(c=0;c<3;c++)

{

printf("\n enter the value=");

scanf("%d%d",&a[r][c],&b[r][c]);

}

}

printf("\n first matrix=\n");

for(r=0;r<=3;r++)

{

for(c=0;c<3;c++)

{

printf("%d\t",a[r][c]);

}

printf("\n");

}

printf("\n scond matrix=\n");

for(r=0;r<=3;r++)

{

for(c=0;c<3;c++)

{printf("%d\t",b[r][c]);

}

printf("\n");

}

printf("\n sum of given matrix=\n");

for(r=0;r<=3;r++)

{

for(c=0;c<3;c++)

{

c[r][c]=a[r][c]+b[r][c];

printf("%d\t",c[r][c]);

}

printf("\n");

}

getch();

}

Answer 2

#include

void main()

{

int mat[10][10];

int i,j;

int m,n;

int sumrow,sumcol;

cout<<\nenter the order of matrix;

cin>>m>>n;

cout<<\nenter elements of a matrix;

for(i=0;i<m;i++)

{

for(j=0;j<n;j++)

cin>>mat[i][j];

}

for(i=0;i<m;i++)

{

sumrow=0;

for(j=0;j<n;j++)

sumrow=sumrow+mat[i][j];

cout<<"\n the sum of"<<i<<"row="<<sumrow;

}

for(j=0;j<n;j++)

{

sumcol=0;

for(i=0;i<m;i++)

sumcol=sumcol+mat[i][j];

cout<<\nthe sum of"<<j<<"column="<<sumcol;

}

Answer 3

#include <stdio.h>

main()

{

int a[5][5];

for (int i=0;i<5;i++)

{

for(int j=0;j<5;j++)

{

a[i][j]=10+j+i;

}

}

for (int i=0;i<5;i++)

{

printf("%d\n",a[i][i]);

}

}

Answer 4

void main() { int arr1[3][3],arr2[3][3];
int i,j;
for(i=0;i<3;i++) //insertion of element of first array
{ for(j=0;j<3;j++)
{ scanf("%d",&arr1[i][j]);
}
}
for(i=0;i<3;i++) //elements of second array
{ for(j=0;j<3;j++)
{ scanf("%d",&arr2[i][j]);
}
}
for(i=0;i<3;i++) //addition
{ for(j=0;j<3;j++)
{ arr3[i][j]=arr1[i][j]+arr2[i][j];
}
}
for(i=0;i<3;i++) //output show
{ for(j=0;j<3;j++)
{ printf("%d",&arr[i][j]);
}
}
getch();
}

Answer 5

#include

#include

int main()

{

clrscr();

int A[10][10],m,n,x,y,sum=0;

//Create a Matrix A

cout << "Enter number of rows and columns in Matrix A : \n";

cin>>n>>m;

cout << "Enter elements of Matrix A : \n";

for(x=1;x

for(y=1;y

cin>>A[x][y];

//Find sum of each row

for(x=1;x

{

A[x][m+1]=0;

for(y=1;y

A[x][m+1]=A[x][m+1]+A[x][y];

}

//Find sum of each column

for(y=1;y

{

A[n+1][y]=0;

for(x=1;x

A[n+1][y]+=A[x][y];

}

cout << "\nMatrix A, Row Sum (Last Column)" << " and Column Sum (Last Row) :\n";

for(x=1;x

{

for(y=1;y

cout << A[x][y] << " ";

cout << "\n";

}

//Print sum of each column

x=n+1;

for(y=1;y

cout << A[x][y] << " ";

cout << "\n";

if(m==n)

{

for(x=1;x

for(y=1;y

if(x==y) sum+=A[x][y];

else if(y==m-(x+1)) sum+=A[x][y];

}

cout << "Sum of diagonal elements is : " << sum << endl;

getch();

return 0;

}

Answer 6

#include

#include

int main()

{

clrscr();

int A[10][10],m,n,x,y,sum=0;

//Create a Matrix A

cout << "Enter number of rows and columns in Matrix A : \n";

cin>>n>>m;

cout << "Enter elements of Matrix A : \n";

for(x=1;x

for(y=1;y

cin>>A[x][y];

//Find sum of each row

for(x=1;x

{

A[x][m+1]=0;

for(y=1;y

A[x][m+1]=A[x][m+1]+A[x][y];

}

//Find sum of each column

for(y=1;y

{

A[n+1][y]=0;

for(x=1;x

A[n+1][y]+=A[x][y];

}

cout << "\nMatrix A, Row Sum (Last Column)" << " and Column Sum (Last Row) : \n";

for(x=1;x

{

for(y=1;y

cout << A[x][y] << " "; cout << "\n"; }

//Print sum of each column x=n+1;

for(y=1;y

cout << A[x][y] << " "; cout << "\n";

if(m==n)

{

for(x=1;x

for(y=1;y

if(x==y) sum+=A[x][y];

else if(y==m-(x+1)) sum+=A[x][y];

}

cout << "Sum of diagonal elements is : " << sum << endl;

getch();

return 0;

}

Answer 7

To find the sum of the diagonals of a given matrix the following code fragment can be used (with suitable definitions and data initialisations):

if (num_rows > num_cols) max = num_cols;

else max = num_rows;

sum = 0;

for (i = 0; i < max; i++) sum += matrix[i][i];

printf("Sum of diagonal elements is %d\n", sum);

Answer 8

#include

int main()

{

int a,b,c;

Answer 9

Yes, please do.